What accounts for the large increase in volume when sugar burns?

¿How do the products of the reaction to the phenol red test and the splint test? Please help me it's for today.! :((

laila [671]

Answer:

The answer in this question is show you made Sodium Hydroxide and Hydrogen Gas.In order to do the products of the reaction relate to the phenol red test and the splint test you need to show that you made Sodium Hydroxide and Hydrogen Gas. Show that you made Sodium Hydroxide and Hydrogen Gas so that the products of the reaction relate to the phenol red test and the splint test.

5 0

3 years ago

A buffer solution contains 0.479 M NaHCO3 and 0.342 M Na2CO3. Determine the pH change when 0.091 mol HNO3 is added to 1.00 L of

pshichka [43]

Answer:

ΔpH = 0.20

Explanation:

The buffer of HCO₃⁻ + CO₃²⁻ has a pka of 10.2

HCO₃⁻ ⇄ H⁺ + CO₃²⁻

There are 0.479moles of NaHCO₃ and 0.342moles of Na₂CO₃.

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.342mol / 0.479mol

pH = 10.05

NaOH reacts with HCO₃⁻ producing CO₃²⁻, thus:

NaOH + HCO₃⁻ → CO₃²⁻ + H₂O + Na⁺

0.091 moles of NaOH produce the same moles of CO₃²⁻ and consume HCO₃⁻. Moles of these species are:

CO₃²⁻: 0.342mol + 0.091mol: 0.433mol

HCO₃⁻: 0.479mol - 0.091 mol: 0.388mol

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.433mol / 0.388mol

pH = 10.25

That means change of pH, ΔpH is:

ΔpH = 10.25 - 10.05 = 0.20

I hope it helps!

3 0

3 years ago

Balance the following

olga55 [171]

Answer:

Your coefficients (the numbers in front of the molecule) will be the following from left to right.

1. 1 - 2 - 1 - 2

2. 2 - 1 - 2 - 2 - 1

3. 2 - 4 - 1

4. 2 - 4 - 3

5. 2 - 2 - 2 - 1

6. 1 - 1 - 1

7. 2 - 1 - 2

8. 3 - 1 - 2 - 3

9. 3 - 1 - 2 - 3

10. 2 - 1 - 1 - 1

Explanation:

To balance this equations first count how many times an element is on each side and then see what needs to be changed in order to balance them.

8 0

1 year ago

11 A student combined 1.2 g of H2 gas and 5.4 g of He gas in a 2.5 L closed container. What was the pressure exerted by the H2 g

blagie [28]

The correct answer is 5.8 atm.

7 0

3 years ago

Read 2 more answers

How many moles of silver nitrate (AgNO3) are needed to produce 6.75 moles of copper (ll) nitrate (Cu(NO3)2) upon reacting with e

Alina [70]

Answer:

13.5 moles of AgNO₃

Explanation:

To determine the reaction:

Reactants: AgNO₃ and Cu

Products: Cu(NO₃)₂ and Ag

2 moles of AgNO₃ react to 1 mol of Cu, in order to produce 1 mol of Cu(NO₃)₂ and 2 moles of solid silver.

2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag

Our production was 6.75 moles of Cu(NO₃)₂

Let's make the rule of three:

1 mol of Cu(NO₃)₂ is produced by 2 moles of AgNO₃

Then, our 6.75 moles were definetely produced by (6.75 . 2) /1 = 13.5 moles.

If the copper was in excess, then the silver nitrate is the limiting reactant:

2 mol of AgNO₃ can produce 1 mol of Cu(NO₃)₂

Then, 13.75 moles of silver nitrate must produce (13.5 . 1) /2 = 6.75 moles of Cu(NO₃)₂

6 0

3 years ago