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Alex787 [66]
3 years ago
12

Which are examples of short-term environmental change? Check all that apply.

Physics
2 answers:
d1i1m1o1n [39]3 years ago
8 0

Answer:

tsunamis,El Nino,and volcanic eruptions

Explanation:

all short term.

IRISSAK [1]3 years ago
5 0

Answer: tsunamis,El Nino,and volcanic eruptions

Explanation:

the correct answer  for e d g e n u i t y

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A small airplane with a wingspan of 18.0 m is flying due north at a speed of 63.6 m/s over a region where the vertical component
choli [55]

Answer:

(a) ε = 1373.8.

(b) The wingtip which is at higher potential.

Explanation:

(a) Finding the potential difference between the airplane wingtips.

Given the parameters

wingspan of the plane is = 18.0m

speed of the plane in north direction is = 70.0m/s

magnetic field of the earth is = 1.20μT

The potential difference is given as:

ε = Blv

where ε = potential difference of wingtips

B = magnetic field of earth

l = wingspan of airplane

v = speed of airplane

ε = 1.2 x 18.0 x 63.6

ε  = 1373.8

(b) Which wingtip is at  higher potential?

The wingtip which is at higher potential.

5 0
3 years ago
Erica is working in the lab. She wants to remove the fine dust particles suspended in a sample of oil. Which method is she most
mash [69]
Option a is right answer that is reverse osmosis.
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3 years ago
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A car traveling at 30 m/s north slows to a stop in 15 seconds. What is the acceleration? PLEASE HELP
Lapatulllka [165]
The answer is C..........
6 0
3 years ago
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A 100-newton box is placed on a table. The table can exert a maximum normal force of 80 newtons. What will happen to the box?
myrzilka [38]

Answer:

D

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Dddddddddddddddddd

8 0
4 years ago
A 35-year-old patent clerk needs glasses of 50-cm focal length to read patent applications that he holds 25 cm from his eyes. Fi
Natali5045456 [20]

Answer:

28.57 cm

Explanation:

We are given that

Focal length,f=50 cm

Distance of application from his eyes,s=40 cm

\frac{1}{s}+\frac{1}{s'}=\frac{1}{f}

\frac{1}{40}+\frac{1}{s'}=\frac{1}{50}

\frac{1}{s'}=\frac{1}{50}-\frac{1}{40}=\frac{4-5}{200}

s'=\frac{200}{-1}=-200 cm

s=25 cm

Substitute the values

\frac{1}{25}-\frac{1}{200}=\frac{1}{f'}

\frac{8-1}{200}=\frac{1}{f'}

\frac{1}{f'}=\frac{7}{200}

f'=\frac{200}{7}=28.57 cm

6 0
3 years ago
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