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Troyanec [42]
3 years ago
5

The electric force between two charged vinyl balloons is 3.0 × 10-3 newtons. If the distance between them is 6.0 × 10-2 meters a

nd the charge of one vinyl balloon is 3.3 × 10-8 coulombs, what is the charge on the other vinyl balloon? (k = 9.0 × 109 newton·meter2/coulombs2) 3.3 × 10-8 coulombs 3.6 × 10-8 coulombs 4.8 × 10-8 coulombs 6.0 × 10-8 coulombs 3.3 × 10-3 coulombs
Physics
1 answer:
irakobra [83]3 years ago
8 0
The electric force between two objects can be understood by looking at Coulomb's Law. The law states that the electric force is directly proportional to the charges of the 2 objects, and inversely proportional as the square of the distance. This is shown below:

F = (k * Q1 * Q2) / d^2

Where: k = proportionality constant; Q1 = charge of object 1; Q2 = charge of object 2; d = distance between objects.

Given:

F = <span>3.0 × 10^-3 N
Q1 = </span>3.3 × 10^-8 coulombs<span>
Q2 = ?
d = </span><span>6.0 × 10^-2 m
</span><span>k = 9.0 × 10^9

Substituting:

3 x 10^-3 = (9 x 10^9 * 3.3 x 10^-8 * Q2) / (6 x 10^-2)^2
[(</span>3 x 10^-3) * (6 x 10^-2)^2] / [(<span>9 x 10^9) * (3.3 x 10^-8)</span>] = Q2
Q2 = 3.636 x 10^-8 coulombs
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Answer:

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00  m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

r'=\sqrt{d^2+r^2}

Where, d = distance between two identical loudspeakers

r = distance between speakers and listener

Put the value into the formula

r'=\sqrt{(1.00)^2+(4.00)^2}

r'=\sqrt{1.00+16.00}

r'=4.12\ m

We need to calculate the path difference

Using formula of path difference

|r'-r|=4.12-4.00

|r'-r|=0.12\ m

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{v}{f}

Where, v = speed of sound

f = frequency

Put the value into the formula

\lambda=\dfrac{343}{300}

\lambda=1.143\ m

We need to calculate the phase difference

Using formula of phase difference

\phi=\dfrac{2\pi\times|r'-r| }{\lambda}

\phi=\dfrac{2\pi\times0.12}{1.143}

\phi=0.659\ rad

Hence, The phase difference is 0.659 rad.

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