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2 years ago

Calculate the electric current that flows through a electric heater of power 1000watt when collected with 220 volt ac supply

Physics

1 answer:

Anit [1.1K]2 years ago

5 0

Answer:

4.545 A

Explanation:

From the question,

Using,

P = VI....................... Equation 1

Where P = power of the heater, V = Voltage supply, I = Electric current that flows through the heater

make I the subject of the equation above

I = P/V.................. Equation 2

Given: P = 1000 watt, V = 220 volt.

Substitute these values into equation 2

I = 1000/220

I = 4.545 A

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A thin double convex glass lens with an index of 1.56 while surrounded by air has a 10 cm focal length. If it is placed under wa

bearhunter [10]

Explanation:

Formula which holds true for a leans with radii $R_{1}$ and $R_{2}$ and index refraction n is given as follows.

$\frac{1}{f} = (n - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

Since, the lens is immersed in liquid with index of refraction $n_{1}$ . Therefore, focal length obeys the following.

$\frac{1}{f_{1}} = \frac{n - n_{1}}{n_{1}} [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

$\frac{1}{f(n - 1)} = [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

and, $\frac{n_{1}}{f(n - n_{1})} = \frac{1}{R_{1}} - \frac{1}{R_{2}}$

or, $f_{1} = \frac{fn_{1}(n - 1)}{(n - n_{1})}$

$f_{w} = \frac{10 \times 1.33 \times (1.56 - 1)}{(1.56 - 1.33)}$

= 32.4 cm

Using thin lens equation, we will find the focal length as follows.

$\frac{1}{f} = \frac{1}{s_{o}} + \frac{1}{s_{i}}$

Hence, image distance can be calculated as follows.

$\frac{1}{s_{i}} = \frac{1}{f} - \frac{1}{s_{o}} = \frac{s_{o} - f}{fs_{o}}$

$s_{i} = \frac{fs_{o}}{s_{o} - f}$

$s_{i} = \frac{32.4 \times 100}{100 - 32.4}$

= 47.9 cm

Therefore, we can conclude that the focal length of the lens in water is 47.9 cm.

4 0

2 years ago

What is Newton's third law ?

tatyana61 [14]

Answer:

every action has an equal and opposite reaction

plz mark me brainliest

3 0

2 years ago

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What could you add to a closed circuit consisting of 2 batteries, 2 light bulbs, and a switch to Increase the current?

Brilliant_brown [7]

Answer:

The following that could be used to make the simplest circuit are a battery, wire, switch, and a light bulb. The answer is letter D. The battery provides the energy for the bulb to work. The wire provides a pathway for the electrons to move. The switch provides the open and close of the circuit.

Explanation:

Hopefully this helped, if not HMU and I will get u a better answer

-Have a great day! :)

4 0

3 years ago

Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the

leonid [27]

Answer:

$KE_A=33\ J$

$KE_B=99\ J$

Explanation:

Given:

Let mass of the particle B be, $m_B=m$

then the mass of particle A, $m_A=3m$

Energy stored in the compressed spring, $E=132\ J$

Now when the compression of the particles with the spring is released, the spring potential energy must get converted into the kinetic energy of the particles and their momentum must be conserved.

Kinetic energy:

$\frac{1}{2}m_A.v_A^2+\frac{1}{2}m_B.v_B^2=132$