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Anton [14]
3 years ago
11

Calculate the electric current that flows through a electric heater of power 1000watt when collected with 220 volt ac supply

Physics
1 answer:
Anit [1.1K]3 years ago
5 0

Answer:

4.545 A

Explanation:

From the question,

Using,

P = VI....................... Equation 1

Where P = power of the heater, V = Voltage supply, I = Electric current that flows through the heater

make I the subject of the equation above

I = P/V.................. Equation 2

Given: P = 1000 watt, V = 220 volt.

Substitute these values into equation 2

I = 1000/220

I = 4.545 A

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A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy
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Answer:

21.21 m/s

Explanation:

Let KE₁ represent the initial kinetic energy.

Let v₁ represent the initial velocity.

Let KE₂ represent the final kinetic energy.

Let v₂ represent the final velocity.

Next, the data obtained from the question:

Initial velocity (v₁) = 15 m/s

Initial kinetic Energy (KE₁) = E

Final final energy (KE₂) = double the initial kinetic energy = 2E

Final velocity (v₂) =?

Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:

KE = ½mv²

NOTE: Mass (m) = constant (since we are considering the same car)

KE₁/v₁² = KE₂/v₂²

E /15² = 2E/v₂²

E/225 = 2E/v₂²

Cross multiply

E × v₂² = 225 × 2E

E × v₂² = 450E

Divide both side by E

v₂² = 450E /E

v₂² = 450

Take the square root of both side.

v₂ = √450

v₂ = 21.21 m/s

Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.

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3 years ago
If you are traveling around a curve at a constant speed of 30 km/h, is your velocity changing?
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