How much heat is required to convert 0.3 kilogram of ice at 0°C to water at the same temperature

Physics

2 answers:

Grace [21]3 years ago

6 0

Answer:

100,200J of heat is required to convert 0.3kg of ice of 0°C to water at same temperature.

Explanation:

Heat = mass * lf

Latent heat of fusion (lf) of water is 334J/g

Heat = 300g * 334 J/g

Heat = 100,200J of heat

irina1246 [14]3 years ago

6 0

Answer:

100800 J

Explanation:

Specific Latent heat of fusion of water: This is the quantity of heat required to change the unit mass of water from ice to liquid without change in temperature.

The expression for Specific latent heat of fusion is given as

Q = Cm...................... Equation 1

Where Q = Amount of heat, C = Specific latent heat of fusion of ice, m = mass of ice.

Given: m = 0.3 kg,

Constant: C = 336000 J/kg

substitute into equation 1

Q = 336000(0.3)

Q = 100800 J.

You might be interested in

Why did the “yielders” conform in Asch’s experiment?

svet-max [94.6K]

Answer:

Asch's experiment showed that about 75% of people were "yielders" who conformed and 25% were "independent" who didn't conform. Asch concludes that people ignored reality and gave an incorrect answer in order to follow the rest of the group.

4 0

2 years ago

A ball is thrown straight up with a velocity of 50 m/s.(use g = -10 m/s^2) a) What is the velocity in m/s after 2 seconds?

Andrei [34K]

Answer:

(a) 30 m/sec

(b) -50 m/sec

Explanation:

We have given initial velocity of ball u = 50 m/sec

Acceleration due to gravity $g=-10m/sec^2$