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Kaylis [27]
3 years ago
10

A lab group was measuring the mass of an object. They recorded the following masses for the same object: 12.13 g, 12.12 g, 12.13

g, and 12.11 g. The actual mass of the object was 17.13 g. Which of the following best describes the lab groups results? The results were both accurate and precise. The results were accurate but not precise. The results were precise but not accurate. The results lacked both precision and accuracy.
Chemistry
1 answer:
Step2247 [10]3 years ago
3 0

Answer:

Precise, but not accurate

Explanation:

First, let’s define accuracy and precision.

⇒Accuracy: how close you are to the actual value

⇒Precision: how close the measurements are to each other.

Let’s examine the data given:  

12.13 g, 12.12 g, 12.13 g, and 12.11 g

Each number is or is very close to 12.12 (within 0.1)

The actual mass of the object is 17.13 grams. Each measurement is about 5 grams away from the actual mass.

Since the measurements are very close to each other, but quite far from the true value, we can say the results are precise, but not accurate.

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Sam buys a package of chips and notices that hydrogenated vegetables oil is one of the ingredients. This ingredient primarily:
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3 years ago
Answer these questions based on 234. 04360 as the atomic mass of thorium-234. The masses for the subatomic particles are given.
nikdorinn [45]

The mass defect for the isotope thorium-234 if given mass is 234.04360 amu is 1.85864 amu.

<h3>How do we calculate atomic mass?</h3>

Atomic mass (A) of any atom will be calculated as:

A = mass of protons + mass of neutrons

In the Thorium-234:

Number of protons = 90

Number of neutrons = 144

Mass of one proton = 1.00728 amu

Mass of one neutron = 1.00866 amu

Mass of thorium-234 = 90(1.00728) + 144(1.00866)

Mass of thorium-234 = 90.6552 + 145.24704 = 235.90224 amu

Given mass of thorium-234 = 234.04360 amu

Mass defect = 235.90224 - 234.04360 = 1.85864 amu

Hence required value is 1.85864 amu.

To know more about Atomic mass (A), visit the below link:

brainly.com/question/801533

4 0
1 year ago
What type of air masses might make up the cold air mass in a cold front
Elena L [17]

Answer:

continental polar air masses

Explanation:

forms over Canada, move down from North Pole, bring bitterly cold and dry air to the northern United States during the winter.

4 0
3 years ago
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Looters break a statue into pieces. How do you expect the weathering of pieces of rock to change?
andreyandreev [35.5K]
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3 years ago
How many moles of xenon gas, Xe, would occopy 37.8L at stp
Charra [1.4K]

Answer:

The number of moles of  xenon are 1.69 mol.

Explanation:

Given data:

Number of moles of xenon = ?

Volume of gas = 37.8 L

Temperature = 273 K

Pressure = 1 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values in formula.

1 atm × 37.8 L = n ×  0.0821 atm.L/ mol.K   ×273 K

37.8 atm.L =  n × 22.413 atm.L/ mol.

n = 37.8 atm.L /  22.413 atm.L/ mol.

n = 1.69 mol

The number of moles of  xenon are 1.69.

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3 years ago
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