Answer:
El volumen del cuerpo es el mismo al comienzo de la experiencia.
Explicación:
El volumen del cuerpo es el mismo al principio porque el volumen no cambia si la temperatura permanece igual. Si cambiamos la temperatura i. mi. Al aumentar la temperatura, las moléculas comienzan a expandirse y se produce un aumento de volumen mientras que cuando disminuimos la temperatura, las moléculas de esa sustancia comienzan a contraerse y el volumen de esa sustancia disminuye. Entonces concluimos que el volumen depende de la temperatura.
Answer is Option-3:
<span>C</span>₆H₁₄ (Hexane)<span> and H</span>₂O are immiscible.
Explanation:
Hexane is a chain of six carbon atoms attached to each other in straight chain and hydrogen atoms. All the bonds in this compound are non-polar. Hexane molecules interact with each other through London Dispersion Forces.
While, Water molecules are polar in nature, due to electronegativity difference between Oxygen and Hydrogen atoms the Hydrogen atom is partially positive and Oxygen atom is partially negative. And water molecles interact with each other through hydrogen bonding.
Result:
As we know LIKE DISSOLVES LIKE, so both Hexane and water are different from each other, so when mixed together thay fail to develop interactions with each other, Hence immiscible in each other.
Answer:
The equilibrium constant is 273.0322
Explanation:
For the given chemical reaction ,
ICE table can be written as -
H₂(g) + I₂(g) ⇄ 2HI(g)
initial moles 3.85 2.35 -
at equilibrium 3.85 - x 2.35 - x 2x
From question , at equilibrium the concentration of I₂ = 0.0500 M
The concentration of I₂ ( ICE table ) = concentration of I₂ (given in question )
2.35 - x = 0.0500
x = 2.3
Putting the value of x in ICE table , to obtain the concentration terms as-
[H₂] = 3.85 - x
[H₂] = 3.85 - 2.3
[H₂] = 1.55 M
[HI] = 2x
[HI] = 2* 2.3
[HI] = 4.6 M
[I₂] = 0.0500M (Given)
Equilibrium Constant ( Kc )
The value of equilibrium constant is written as the concentration of the products each raised to the power of their respective stoichiometry by the concentration of reactants each raised to the power of their respective stoichiometry.
Kc = [HI]² / [H₂][I₂]
Kc = ( 4.6 )² / (1.55)*(0.0500)
Kc = 273.0322 .