Be and B: Be is 1s2 2s2 and B is 1s2 2s2 2p1
Be has full 2 orbitals and so does B but B only has 1 electron in p so it is really unstable and easy to react. So there is a dip in ionization energies. The other questions are similar to this so if you need, feel free to ask me
The balanced chemical reaction is written as:
2H2+O2 = 2H2O
We are given the amount of H2 gas to be used in the reaction. This will be used as the starting point for the calculations. We calculate as follows:
.050 L H2 ( 1 mol H2 / 22.4 L H2 ) ( 1 mol O2 / 2 mol H2 ) ( 22.4 L / 1 mol ) = 0.025 L O2 or 25 mL O2
I believe that the molar mass is 342.34g/mol
Answer:
The answer to your question is below
Explanation:
Trial 1 Trial 2
mass of Mg 0.255 g 0.353 g
mass of MgO 0.418 g 0.576 g
Chemical reaction
2Mg(s) + O₂(g) ⇒ 2MgO(s)
Question 1.
Atomic mass of Mg = 24.31 x 2 = 48.62 g
Molecular mass of MgO = 2(24.31 + 16) = 80.62 g
Trial 1
48.62 g of Mg ----------------- 80.62 g of MgO
0.255 g ---------------- x
x = (0.255 x 80.62)/48.62
x = 0.422 g of MgO
Trial 2 48.62 g of Mg ----------------- 80.62 g of MgO
0.353 g ---------------- x
x = (0.353 x 80.62)/48.62
x = 0.585 g of MgO
Question 2
Trial 1
Percent yield = 0.418/0.422 x 100 = 99%
Trial 2
Percent yield = 0.576/0.585 x 100 = 98.5%
Question 3
Average = (99 + 98.5)/2
= 98.75%
Answer:
Save the *minerals* used to extract metals.
