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3 years ago

Which particle is most likely present in the nucleus of the atom

Chemistry

2 answers:

k0ka [10]3 years ago

8 0

Oh protons and neutrons

DIA [1.3K]3 years ago

6 0

Explanation:

An atom consists of three subatomic particles. These are protons, electrons and neutrons.

A proton has a positive charge, an electron has a negative charge and a neutron has no charge.

A nucleus is the central part of an atom. And, inside the nucleus there are protons and neutrons. Whereas electrons move in circular path outside the nucleus.

Hence, we can conclude that most likely protons and neutrons are present in the nucleus of the atom.

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What is the name for the chemical compound NaBr and is it ionic or covalent

DochEvi [55]

Answer: Sodium bromide is an ionically bonded compound.

(NaBr: Sodium Bromide)

8 0

2 years ago

If you lift an object that weighs 13 pounds through a distance of 3 feet, you have done foot-pounds of work.

Katyanochek1 [597]

The answer to your statement is true

3 0

3 years ago

Read 2 more answers

In a 63.17 g sample of SO3, how many grams are sulfur?

Evgesh-ka [11]

Answer:

25.30 gram

Explanation:

No of moles = given mass / molar mass

No of moles = 63.17/80.06

0.7890 moles

Mass of sulphar = no of moles× molar mass of sulphar

Mass of sulphur = 0.7890×32.065

25.30 gram

4 0

3 years ago

What is the silver ion concentration in a solution prepared by mixing 369 mL 0.373 M silver nitrate with 411 mL 0.401 M sodium c

LuckyWell [14K]

Answer:

[A g + ] = 3.12 *10^-6 M

Explanation:

Step 1: Data given

Volume silver nitrate = 369 mL

Molarity silver nitrate = 0.373 M

Volume sodium chromate = 411 mL

Molarity sodium chromate = 0.401 M

The Ksp of silver chromate is 1.2 * 10^− 12

Step 2: The balanced equation

2 A g + ( a q ) + C rO4^2- ( a q ) →Ag2CrO4 ( s)

Step 3:

[Ag+]i = [AgNO3] * V1/(V1+V2) * 1 mol Ag+ / 1 mol AgNO3

[Ag+]i = 0.373 M * 0.369/ (0.369+0.411)

[Ag+]i = 0.176 M

[C rO4^2]i = [Ag2CrO4] * V2 /(V1+V2) * 1mol C rO4^2 / 1 mol Ag2CrO4

[C rO4^2i = 0.401 M * 0.411 / (0.369+0.411)

[C rO4^2]i = 0.211 M

Ksp = [Ag+]²[CrO4^2-] = 1.2 * 10^− 12

[CrO4^2-]f = [CrO4^2-]i - 0.5 * [Ag+]i

[CrO4^2-]f = 0.211 -0.088 = 0.123 M

1.2 * 10^− 12 = ( 2 x ) ²*( 0.123M + x )

[ C O 3^ −2] f >> x

1.2 * 10^− 12 = ( 2 x ) ²* 0.123M

x = 1.56 * 10^-6

[A g + ] f = 2x = 3.12 *10^-6 M

4 0

3 years ago

Construct a simulated 1H NMR spectrum for ethyl acetate by dragging and dropping the appropriate splitting patterns into the box

Ksju [112]

Answer:

The simulated 1H NMR spectrum for ethyl acetate is shown in the drawing attached.

Explanation:

To construct this NMR it is necessary to identify the essential components that can produce resonance peaks.

Two main groups can be identified, the acetyl group containing a sub-component (CH3) capable of producing a resonance peak, and the ethyl group containing two components (CH2 and CH3) each of which can produce on its own its own resonance peak.

6 0

3 years ago