Answer:
6.53 m/s²
Explanation:
Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.
Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:
T = m₁a (1)
m₂g - T = m₂a (2)
substituting T = m₁a in equation 2:
m₂g - m₁a = m₂a
m₂a + m₁a = m₂g
a(m₁ + m₂) = m₂g
a = m₂g / (m₁ + m₂)
a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²
Both objects have an acceleration of 6.53 m/s²
Answer: Kilogram- newton is wrong unit for Torque
Idem pound-inch is also wrong unit for Torque
Explanation: As it is well known the torque is defined as :
Τorque= F x R
so its UNITS are Newton*meter (SI)
or in the Imperial System is often use Pound-foot
Most likely by moving an object and by moving it from one place to another and how fast and slow it goes to its destination.
I couldnt type it out so here's a picture
Answer: a) 24.2 rad/s² b) 6.95 rad/s
Explanation:
So the cylinder's moment of inertia is , where M is the mass of the cylinder and R is its radius.
The problem you have here is that the axle is modifying it, so we use the parallel axis theorem:
Therefore
where D is the distance from the center of mass to the axis which is a radius R
Next the Momentum with respect to the center of mass of the cylinder is
because there are no other forces rather than the cylinder's weight, now kg*m^2
a ) replace and find
b) we start by assuming that the energy is conserved because the cylinder is rolling without sliding:
so the potential energy is given by
now you have that the same amount is going to be equal to the kinetic rotational energy of the cylinder so