Answer:
angular acceleration is -0.2063 rad/s²
Explanation:
Given data
mass m = 95.2 kg
radius r = 0.399 m
turning ω = 93 rpm
radial force N = 19.6 N
kinetic coefficient of friction μ = 0.2
to find out
angular acceleration
solution
we know frictional force that is = radial force × kinetic coefficient of friction
frictional force = 19.6 × 0.2
frictional force = 3.92 N
and
we know moment of inertia that is
γ = I ×α = frictional force × r
so
γ = 1/2 mr²α
α = -2f /mr
α = -2(3.92) /95.2 (0.399)
α = - 7.84 / 37.9848 = -0.2063
so angular acceleration is -0.2063 rad/s²
Answer:
D) 11 m/s
Explanation:
The problem asks us to calculate the velocity of the hot dog with respect to the observer stationary outside the train. This velocity is given by:
where
is the velocity of the train (towards right)
is the velocity of the man (towards right)
is the velocity of the hot-dog (towards left, so we put a negative sign)
Substituting the numbers into the equation, we find
and the positive sign means the velocity is toward right.
A lightbulb carries more current immediately after it is turned on and the glow of the metal filament is increasing; option A.
<h3>What is current?</h3>
Current refers to the flow of electric charges typically electrons.
Current flowing through a metallic material decreases with increase in temperature of the material.
This is because the resistance of the metal increases with increase in temperature.
Therefore, for a light bulb, the current flow through it will be maximum when it is just turned on because the temperature, and hence the resistance of the filament is at its lowest.
In conclusion, current flow decreases with increase in resistance.
Learn more about current and resistance at: brainly.com/question/24858512
#SPJ4
Answer:
April 24, 1990 is the answer
Answer:
110.87 dB
Explanation:
(I got it right on Acellus)
I= P/4(pi)r^2 = 60/4(pi)6.25^2
60/4(pi)6.25^2=0.12223
B=10log(I/Io)
B=10log(0.12223/1*10^-12) = 110.87 dB
111 in sigfigs
