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Temka [501]
3 years ago
10

uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is th

e potential difference between the plates?
Physics
1 answer:
adoni [48]3 years ago
7 0

Answer:

potential difference V= 300 volts

Explanation:

Given:

d= 2.0 cm = 0.02m

E = 15 kN/C = 15 × 10³ N/C

For a uniform field between two plates, the Electric Filed Intensity (E) is proportional to the potential difference (V) and inversely  proportional to distance between the plates.

E= V/d

⇒ V= E×d = 15 × 10³ N/C × 0.02 m = 300 volts  (∴1 Nm/C = 1 J/C= 1 volts)

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The electrons are the only part of the atom that forms the bond
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An apple, potato, and onion all taste the same if you eat them with your nose plugged

Explanation:

3 0
3 years ago
Is it possible to produce a continuous and oriented aramid fiber–epoxy matrix composite having longitudinal and transverse modul
gregori [183]

Answer:

It is not possible to produce continued and oriented fiber.

Explanation:

To solve the problem it is necessary to take into account the concepts related to Fiber volume ratio. The amount of fiber in a fiber reinforced compound corresponds directly to the mechanical properties of the compound. Given the fiber volume fraction, the theoretical elastic properties of a compound can be determined. The elastic modulus of a compound in the fiber direction of a unidirectional compound can be calculated using the following equation:

E = (1-V_f)E_m+V_fE_f

Where,

E is the longitudinal modulus of Elasticity

V_f is the fiber volume ratio

E_m is the elastic modulus of the matrix

E_f is the elastic modulus of the fibers

We need to consult the table of characteristics of Fibers and Reinforcements of Materials, in which they specify that the modulus of elasticity of the aramid fiber-epoxy is

E_f = 131Gpa

Moreover from the statement,

E = 35Gpa

E_m = 3.4Gpa

Replacing in the previous equation,

35 = 3.4 (1-V_f)+131V_f

V_f = 0.25 \rightarrow longitudinal

To make the comparison we now calculate the Fiber volume ratio through the transverse elastic modulus,

E = \frac{E_mE_f}{(1-V_f)E_f+V_fE_f}

Our values are given in this case as:

E = 5.17Gpa\\E_m = 3.4Gpa \\E_f = 131Gpa

Replacing,

5.17 = \frac{3.4*131}{(1-V_f)(131)+V_f*3.4}

V_f = 0.351 \rightarrow transversal

From both cases it is possible to conclude that it is not possible to produce a fiber of the specified material in a continuous and oriented manner, as long as the volume fraction is different in the different cases.

5 0
3 years ago
When reporting the speed, we need to include the value, units and direction the object was traveling.
andre [41]

False: when reporting speed, only value and units are needed, not the direction

Explanation:

Let's start by reminding the difference between speed and velocity:

- Speed is a scalar quantity which tells "how fast" an object is moving, regardless of its direction of motion.

It can be calculated as: follows:

speed = \frac{d}{t}

where :

d is the distance travelled

t is the time interval

Therefore, speed has no direction, so it is written only as a value followed by units: for example, 5 m/s.

- Velocity is a vector quantity given by:

velocity = \frac{d}{t}

where :

d is the displacement of the object (which is a vector connecting the initial position to the final position of motion)

t is the time interval

Since it is a vector, velocity has both magnitude and direction, therefore it also takes into account the direction of motion of the object. An example of velocity is 5 m/s east, where the direction is also specificied.

Learn more about speed and velocity:

brainly.com/question/8893949

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8 0
3 years ago
A mass is tied to a string and swung in a horizontal circle with a constant angular speed. show answer No Attempt If this speed
Liono4ka [1.6K]

Answer:

The tension in the string is quadrupled i.e. increased by a factor of 4.

Explanation:

The tension in the string is the centripetal force. This force is given by

F = \dfrac{mv^2}{r}

m is the mass, v is the velocity and r is the radius.

It follows that F \propto v^2, provided m and r are constant.

When v is doubled, the new force, F_1, is

F_1 = \dfrac{m(2v)^2}{r} = \dfrac{4mv^2}{r} = 4\dfrac{mv^2}{r} = 4F

Hence, the tension in the string is quadrupled.

8 0
4 years ago
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