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Temka [501]
3 years ago
10

uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is th

e potential difference between the plates?
Physics
1 answer:
adoni [48]3 years ago
7 0

Answer:

potential difference V= 300 volts

Explanation:

Given:

d= 2.0 cm = 0.02m

E = 15 kN/C = 15 × 10³ N/C

For a uniform field between two plates, the Electric Filed Intensity (E) is proportional to the potential difference (V) and inversely  proportional to distance between the plates.

E= V/d

⇒ V= E×d = 15 × 10³ N/C × 0.02 m = 300 volts  (∴1 Nm/C = 1 J/C= 1 volts)

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Masteriza [31]

You would be correct.

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Hope this helps!

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3 years ago
The definition of Force
Gnoma [55]

Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object.

Explanation:

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If the diffusion coefficient doubles, and the average diffusion distance across a membrane remains the same, what can be said ab
Alex777 [14]

Answer:

<u>time taken will be halved</u>

Explanation:

we have

t=\frac{x^{2}}{2D}   ..................(1)

where

t = time elapsed since diffusion began

x^{2} = mean distance traveled by the diffusion solute

D = Diffusion coefficient

now, according to the conditions given in the question

when, diffusion coefficient (D) doubles i.e D' = 2D

Average diffusion distance remains same i.e x' = x

substituting the values in the equation we get

t=\frac{x'^{2}}{2D'}

or

t=\frac{x^{2}}{2(2D)}

or

t=\frac{x^{2}}{4D} ...............(2)

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6 0
3 years ago
C= 5/9 (F−32) The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured i
iren [92.7K]

Answer:

option d) is correct

Explanation:

Given:

C = (5/9)(F-32)

For statement I

C = (5/9)F - (5/9)32

let the initial temperature in Fahrenheit  be 0

thus,

C = (5/9)(0) - (5/9)32 = - (5/9)32

for 1° increase in Fahrenheit

we get

C = (5/9)(1) - (5/9)32 = 1 - (5/9)32

thus,

on comparing the results, statement I is true

now for statement II

let the initial temperature in Celsius  be 0

thus,

0 = (5/9)(F) - (5/9)32

or

F =  (9/5)(5/9)32 = 32

for 1° increase in Celsius

we get

1 = (5/9)(F) - (5/9)32

or

(5/9)F = 1 + (5/9)32

or

F = (9/5) + 32

or

F = 1.8 + 32

thus,

on comparing the results, statement II is true

Now, for statement III

let the initial let the initial temperature in Fahrenheit  be 0

thus,

C = (5/9)(0) - (5/9)32 = - (5/9)32 = - 17.77

for (5/9)° increase in Fahrenheit

we get

C = (5/9)(5/9) - (5/9)32 = (0.3086) - 17.77 = -17.469

thus,

on comparing the results, statement III is false

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Answer

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