Change in electric potential energy: 121.5 nJ
Explanation:
For a charged particle moving in an electric field, the change in electric potential energy of the particle is given by
where:
q is the charge of the particle
is the potential difference between the initial and final position of the particle
For the point charge in this problem, we have:
is the charge
is the potential difference
Therefore, the change in electric potential energy is
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Answer:
α = 2,857 10⁻⁵ ºC⁻¹
Explanation:
The thermal expansion of materials is described by the expression
ΔL = α Lo ΔT
α =
in the case of the bar the expansion is
ΔL = L_f - L₀
ΔL= 1.002 -1
ΔL = 0.002 m
the temperature variation is
ΔT = 100 - 30
ΔT = 70º C
we calculate
α = 0.002 / 1 70
α = 2,857 10⁻⁵ ºC⁻¹