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jek_recluse [69]
3 years ago
10

A point charge q = +4.50 nC moves through a potential difference ΔV = Vf − Vi = +27.0 V. What is the change in the electric pote

ntial energy?
ΔUE = _ nJ
Physics
1 answer:
olganol [36]3 years ago
6 0

Change in electric potential energy: 121.5 nJ

Explanation:

For a charged particle moving in an electric field, the change in electric potential energy of the particle is given by

\Delta U = q \Delta V

where:

q is the charge of the particle

\Delta V is the potential difference between the initial and final position of the particle

For the point charge in this problem, we have:

q=+4.50 nC is the charge

\Delta V=+27.0 V is the potential difference

Therefore, the change in electric potential energy is

\Delta U=(+4.50)(+27.0)=121.5 nJ

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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russell westbrook has a mass of 84.8kg.When jumps to dunk on z 3.04 meter goal,what will be his G.P.E at the apex of his jump?
horrorfan [7]

The gravitational potential energy is 2526 J

Explanation:

The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in the gravitational field. Near the Earth's surface, it can be calculated as

GPE=mgh

where

m is the mass of the body

g=9.8 m/s^2 is the acceleration of gravity

h is the height of the object

In this problem, we have

m = 84.8 kg

h = 3.04 m

Substituting,

GPE=(84.8)(9.8)(3.04)=2526 J

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6 0
3 years ago
Solve a hollow steel shaft has an outside diameter of 100mm and inside diameter of 75 mm.the shaft is subjected to a pure torque
FrozenT [24]
  • The maximum shearing stress in hollow shaft is 66.125 MPa.
  • The magnitude of angle of twist is 0.0279 rad.
  • The power generated by the shaft is  157 kW.

<h3>What is power ?</h3>

Power in a rotating body like shaft is the product of Torque and the angular speed of that shaft.

P = Tω

The Torque is related to the shearing stress is

T = π/16 xτ(Do³ -Di³)

* Given is the Torque T= 7.5 kN.m, the inner diameter Di = 0.075m, outer diameter Do= 0.1m

Then, the maximum shearing stress will be

7.5 x 10³ =  π/16 xτ x (0.1³ - 0.075³)

τ = 66.125 MPa

Thus, the shearing stress is 66.125 MPa.

* From the Torque equation

T/J = Gθ/l

Where, J = π/32 (Do⁴ -Di⁴) = 0.00000671 m⁴

l = length of shaft = 2m, modulus of rigidity G = 80GPa = 80x 10⁹ Pa.

Substitute the values, we get the angle of twist

7.5 x10³ /0.00000671 = 80x 10⁹xθ/2

θ = 0.0279 rad.

Thus, the angle of twist is0.0279 rad.

* Power generated by the shaft is

P = 2πNT/60

where N = revolution/ minute = 200

Put the values, we get

P =  2π x 200 x 7500/60

P = 157 kW.

Thus, the power generated is 157 kW.

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5 0
2 years ago
Container A and container B hold samples of the same ideal gas. The volume and the pressure of container A is equal to the volum
SVETLANKA909090 [29]

Answer:

A. TA = TB/2.

Explanation:

Since container A has half as many molecules of the ideal gas in it as container B. Therefore, container A will have half the volume of gas as in container B:

V_A = \frac{1}{2}V_B

Now, from Charle's Law:

\frac{V_A}{T_A}=\frac{V_B}{T_B}\\\\\frac{1}{2}\frac{V_B}{T_A}=\frac{V_B}{T_B}\\\\T_A = \frac{T_B}{2}

Hence, the correct option is:

<u>A. TA = TB/2.</u>

6 0
2 years ago
Are oil and water optically different
katovenus [111]

Answer:

Yes

Explanation:

Trust me

6 0
3 years ago
Read 2 more answers
Two tiny, spherical water drops, with identical charges of −8.00 ✕ 10^(−17) C, have a center-to-center separation of 2.00 cm.
Damm [24]

Answer:

F=1.4384×10⁻¹⁹N

Explanation:

Given Data

Charge q= -8.00×10⁻¹⁷C

Distance r=2.00 cm=0.02 m

To find

Electrostatic force

Solution

The electrostatic force between between them can be calculated from Coulombs law as

F=\frac{kq^{2} }{r^{2} }

Substitute the given values we get

F=\frac{(8.99*10^{9} )*(-8.00*10^{-17} )^{2} }{(0.02)^{2} }\\ F=1.4384*10^{-19} N

7 0
3 years ago
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