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Cerrena [4.2K]
2 years ago
9

You have two balls of equal size and smoothness, and you can ignore air resistance. One is heavy, the other is much lighter. You

hold one in each hand at the same height above the ground. You release them at the same time. What will happen?
Physics
1 answer:
motikmotik2 years ago
4 0

Answer:

They will hit the ground at the same time.

Explanation:

By ignoring the opposing forces i.e. air resistant, both the heavy and light balls will fall with same acceleration due to gravity (g=9.8 m/s²) and g is independent of mass of the objects. Thus both will hit the ground at the same time.

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The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

Therefore, option A is correct option.

Given,

Mass m = 14g

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