Answer:
4.14 m
Explanation:
In the last leg of the journey the ball covers 2 m in 2ms or 0.2 s .
Let in this last leg , u be the initial velocity.
s = ut + 1/2 g t²
2 = .2 u + .5 x 9.8 x .04
u = 9.02 m /s .
Let v be the final velocity in this leg
v² = u² + 2 g s
v² = (9.02)² + 2 x 9.8 x 2
= 81.36 +39.2
v = 10.97 m / s
Now consider the whole height from where the ball dropped . Let it be h.
Initial velocity u = 0
v² = u² +2gh
(10.97 )² = 2 x 9.8 h
h = 6.14 m
Height from window
= 6.14 - 2m
= 4.14 m
Answer:
The required steady force of each rocket is 28.79 N
Explanation:
mass of the satellite, M=3900 kg
radius, r=4.3 m
mass of rocket, m=210 kg
time, t=5.4 min
Moment of Inertia:
I = 1/2 (Mr^2) + 4mr^2
I = 1/2 ( 3900* (4.3)^2) + 4 (210)*(4.3)^2
I = 51587.1 kg m^2
the angular acceleration is:
a= w/t
here w= 2*π*30
so,
a= 2*π*30 / 5.4* 3600
a=0.0096 rad/ s^2
the Torque becomes:
T=I*a = 4r*F
( 51587.1 )*(0.0096) = 4*4.3* F
F= 28.79 N
the required steady force of each rocket is 28.79 N
learn more about steady force here:
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Answer:
Portuguese explorer Vasco de Gama becomes the first European to reach India via the Atlantic Ocean when he arrives at Calicut on the Malabar Coast. Da Gama sailed from Lisbon, Portugal, in July 1497, rounded the Cape of Good Hope, and anchored at Malindi on the east coast of Africa.
Explanation:
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