The solution for this problem:
Given:
f1 = 0.89 Hz
f2 = 0.63 Hz
Δm = m2 - m1 = 0.603 kg
The frequency of mass-spring oscillation is:
f = (1/2π)√(k/m)
k = m(2πf)²
Then we know that k is constant for both trials, we have:
k = k
m1(2πf1)² = m2(2πf2)²
m1 = m2(f2/f1)²
m1 = (m1+Δm)(f2/f1)²
m1 = Δm/((f1/f2)²-1)
m 1 = 0.603/
(0.89/0.63)^2 – 1
= 0.609 kg or 0.61kg or 610 g
Answer:

east of south
Explanation:
Given:
- distance of the person form the initial position,

- direction of the person from the initial position,
north of east
- distance supposed to travel form the initial position,

- direction supposed to travel from the initial position, due North
<u>Now refer the schematic for visualization of situation:</u>

...............(1)

.................(2)
<u>Now the direction of the desired position with respect to south:</u>


east of south
<u>Now the distance from the current position to the desired position:</u>



Answer:
ξ = 0.00845020162 V or 8.4 mV
Explanation:
Magnetic flux measures the total magnetic field that passes through a known area. Magnetic flux describe the effect of magnetic field in a given area. Mathematically,
magnetic flux (Ф) = BA cos ∅
where
A = test area
B = magnetic field
before the flip
Ф = Bπr²N
N = number of turn
magnitude of induced emf = N |ΔФ/Δt|
ξ = 2Nπr²B/dt
ξ = 2 × 22 × π × (1.02/2)² × 0.000047/0.2
ξ = 44 × π × 0.51² × 0.000047/0.2
ξ = 44 × π × 0.2601 × 0.000047/0.2
ξ = 0.0005378868 × 3.142/0.2
ξ = 0.00169004032/0.2
ξ = 0.00845020162 V or 8.4 mV
There is no certain time on how long it takes. Because the factors will always be different and the factors heavily affect the evaporation time. Some factors include: humidity, heat, how the sun is visible (whether clouds are covering it or not)
2.1) (i) W = mg downwards
(ii) N = R = Normal Reaction from the ground upwards
(iii) Fe = Force of engine towards the right
(iv) f = friction towards the left
(v) ma = Constant acceleration towards right.
2.2.1)
v = 25 m/s
u = 0 m/s
∆v = v - u = (25 - 0) m/s = 25 m/s
x = X
∆t = 50 s

a = 0.5 m/s².
2.2.2)
F = ma = 900 kg × 0.5 m/s² = 450 N.
2.2.3)


2.3)
Fe = f + ma
Fe - f = ma
For velocity to be constant,
a should be 0, or, a = 0,
Fe = f = 270 N
2.4.1)
v = 0
u = 25 m/s
a = -0.5 m/s²
v = u + at
t = -u/a = -(25)/(-0.5) = 50 s.
2.4.2)
x = -625/(2×(-0.5)) = 625 m.