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Agata [3.3K]
3 years ago
9

Vector A with rightwards arrow on top has a magnitude of 12m and its direction is 120o counterclockwise from the x axis. What ar

e the magnitude and direction of the vector minus 2 A with rightwards arrow on top? The direction is represented by a counterclockwise angle from the +x axis
(A) 24m, -120o
(B) 24m, -300o
(C) -24m, -120o
(D) 24m, 300o
(E) -24m, 300o
Physics
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

D) 24m, 300o

Explanation:

The vector A has magnitude of 12 m and it makes 120 degree with + ve x axis

So it can be represented by the vector as follows

A = 12 Cos 120 i + 12 sin 120 j

vector 2A = 24 Cos 120 i + 24 sin 120 j

- 2A = - 24 Cos 120 i - 24 sin 120 j

= 24 Cos ( 180 -120 ) - 24 sin ( 180 -120)

= 24 Cos 60 - 24 sin 60

= 24 Cos ( 360 - 60 ) + 24 sin ( 360 -60 )

= 24 Cos 300 + 24 sin 300

It represents a vector having magnitude of 24 and making 300 degree with + ve x- axes in anticlockwise direction.

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The ocean current the question talks about is the following:
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5 0
4 years ago
What force does it take to accelerate a 9.2 kg object 7.0 m/s^2?
Ulleksa [173]

Answer:

<h2>64.4 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

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acceleration = 7 m/s²

We have

force = 9.2 × 7 = 64.4

We have the final answer as

<h3>64.4 N</h3>

Hope this helps you

5 0
3 years ago
An Airbus A320 jetliner has a takeoff mass of 75,000 kg. It reaches its takeoff speed of 82 m/s (180 mph) in 35 s. What is the t
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Answer:

175.5 kN

Explanation:

We find the acceleration of the Airbus A320 jetliner from,

a = (v - u)/t where u = initial velocity of jetliner = 0 m/s (since it starts from rest), v = final velocity of jetliner = 82 m/s and t = time for velocity change = 35 s

So a = (v - u)/t = (82 m/s - 0 m/s)/35 s = 82 m/s ÷ 35 s = 2.34 m/s²

Now, the thrust of the engines on the jetliner T = ma where m = mass of jetliner = 75,000 kg and a = acceleration of jetliner = 2.34 m/s²

T = ma

= 75,000 kg × 2.34 m/s²

= 175500 N

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How much work must be done on a 750 kg car to slow it down from 1.0 x 10 km/h to 2<br> 50.0 km/h?
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Answer:

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8 0
3 years ago
When operated on a household 110.0-V line, typical hair dryers draw about 1650 W of power. We can model the current as a long st
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Answer:

Current in the hair dryer will be equal to 15 A

Explanation:

We have given that household is operated at 110 volt

So potential difference V =110 volt

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We have to find the current in the hair dryer

We know that power is given as P = VI, here V is potential difference and I is current

So 1650=110\times I

I = 15 A

So current in the hair dryer will be equal to 15 A

4 0
4 years ago
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