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Phantasy [73]
3 years ago
15

Which is an example of a three

Chemistry
2 answers:
malfutka [58]3 years ago
6 0

Answer:

It's A. 120 cubic meters

Minchanka [31]3 years ago
4 0
It’s a.120 cubic meters
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Which overall chemical equation is obtained by combining these intermediate equations?
Juli2301 [7.4K]
The common substance among the product(s) of the first equation and among the reactant(s) in the second equation is H2O(g). We can eliminate that as an intermediate. The overall chemical equation will thus be:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(l),

which is the first answer choice.

In essence, all you’re doing here is swapping water vapor for liquid water.
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3 years ago
How to do part (b)??
laila [671]

it has less tightly bound electrons, is able to lose electron easily as compare to metal B at it has 4 unpaired electron in 3d sub-shell.

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3 years ago
What type of mixture is separated by effusion and condensation?
icang [17]

Answer:

c is the answer then check it out

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3 years ago
What is the concentration (in M) of a sample of the unknown dye with an absorbance of 0.25 at 542 nm?
Sladkaya [172]

Answer:

see explanation below

Explanation:

Question is incomplete, so in picture 1, you have a sample of this question with the missing data.

Now, in general terms, the absorbance of a substance can be calculated using the beer's law which is the following:

A = εlc

Where:

ε: molar absortivity

l: distance of the light in solution

c: concentration of solution

However, in this case, we have a plot line and a equation for this plot, so all we have to do is replace the given data into the equation and solve for x, which is the concentration.

the equation according to the plot is:

A = 15200c - 0.018

So solving for C for an absorbance of 0.25 is:

0.25 = 15200c - 0.018

0.25 + 0.018 = 15200c

0.268 = 15200c

c = 0.268/15200

c = 1.76x10⁻⁵ M

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3 years ago
When the following equation is balanced, what is the coefficient for HBr?
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D.) Balanced equation is Zn + 2HBr - - - > ZnBr2 + H2.
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