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yanalaym [24]
3 years ago
9

Making observations is the first step in the scientific method. Why don't scientists stop with the first step when creating an e

xperiment?
A. Scientists don't stop with the first step of their experiment because they don't think that just using their observations is a very good place to start to prove their hypothesis.
B. Scientists don't stop with the first step of their experiment because they not only want to observe but they want to test their observations to be sure they are correct.
C. Scientists don't stop with the first step of their experiment because they want other scientists' opinions because they may not trust their own observations.
D. Scientists don't stop with the first step of their experiment because they would rather plan and run experiments than just observe the world around them.
Chemistry
1 answer:
ankoles [38]3 years ago
6 0
B should be the answer!
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Ice has a lower density than the density of water.
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A sodium atom has 11 protons, 10 electrons, and 12 neutrons. What is its charge
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An ion with 11 protons, 11 neutrons, and 10 electrons would have a charge of 1+, also expressed as a charge of positive one or +1.

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Methane (CH4) burns in oxygen to produce carbon dioxide and water. Which reaction is occurring here?
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B..combustion is the answer
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how many grams of phosphorus (P4) react with 35.5L of O2 at STP to form solid tetraphosphorus decaoxide
algol [13]

Answer:

mass P4 = 35.998 g

Explanation:

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∴ STP: P = 1 atm; T = 298 K

∴ V O2= 35.5 L

⇒ nO2 = P.V / R.T

∴ R = 0.082 atm.L/K.mol

⇒ nO2 = ((1 atm)×(35.5L))/((0.082 atm.L/K.mol)(298K))

⇒ nO2 = 1.453 mol O2

⇒ mol P4 = (1.453 molO2)×(mol P4/ 5molO2) = 0.2906 mol P4

∴ Mw P4 = 123.895 g/mol

⇒ mass P4 = (0.2906 mol P4)×(123.895 g/mol) = 35.998 g P4

4 0
3 years ago
Write the lewis structure for ch2clcoo−. assign a formal charge for any atom with a non-zero formal charge.
Murljashka [212]
The Lewis structure of Chloroacetate (H₂CClCO₂) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with CH₂Cl and O⁻.

Formal Charge;
                        Formal charge is caculated as,

Formal charge  =  # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]

Formal charge on Oxygen (Highlighted Red);

Formal charge  =  6 - [ 6 + 2/2]

Formal charge  =  6 - [6 + 1]

Formal charge  =  6 - [7]

Formal charge  =  -1

8 0
3 years ago
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