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andrew-mc [135]
3 years ago
15

An element is?

Chemistry
2 answers:
Sidana [21]3 years ago
4 0

i think it’s D , not sure though

Maru [420]3 years ago
4 0

Answer:

b;bbbbbbbbbbbbbbbbbb

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What is the universe made of?
OverLord2011 [107]
Matter, air, people, gravity, protons, and space‍♀️
3 0
3 years ago
PLEASE HELP ASAP !!!
Alchen [17]

Answer: Naprox 350 is the anwser

Explanation: because to fourmals mixed makes naprox know as gr27

6 0
4 years ago
When is a Roman numeral most likely needed in the name of an ionic compound
Inessa [10]

Answer:

When the metal of the ionic compound has multiple oxidation states.

Explanation:

Nickel (Ni - At No 28) has multiple oxidation states* => −2, −1, 0, +1,[2] +2, +3, +4[3] (a mildly basic oxide)*. When naming compound of nickel on needs to include a roman numeral in parenthesis after the symbol of the element in order to identify which oxidation state is relevant.

examples

Nickel Halide derivatives include

NiCl => nickel(I) chloride

NiCl₂ => nickel(II) chloride

NiCl₃ => nickel (III) chloride

Such is important in that each of the compounds have different physical and chemical properties due to variations in oxidation states of nickel.

https://en.wikipedia.org/wiki/Nickel

5 0
3 years ago
Read 2 more answers
Given the balanced ionic equation representing the reaction in an operating voltaic cell: zn(s) + cu2+(aq) → zn2+(aq) + cu(s) th
soldi70 [24.7K]

Answer: from the Zn anode to the Cu cathode


Justification:


1) The reaction given is: Zn(s) + Cu₂⁺ (aq) -> Zn²⁺ (aq) +Cu(s)


2) From that, you can see the Zn(s) is losing electrons, since it is being oxidized (from 0 to 2⁺), while Cu²⁺, is gaining electrons, since it is being reduced (from 2⁺ to 0).


3) Then, you can already tell that electrons go from Zn to Cu.


4) The plate where oxidation occurs is called anode, and the plate where reduction occus is called cathode.


So you get that the electrons flow from the anode (Zn) to the cathode (Cu).


Always oxidation occurs at the anode, and reduction occurs at the cathode.

3 0
4 years ago
A woolly rhinocerous skeleton (Coelodonta antiquitatis) found in Poland contains 1.30% of the C-14 found in living animals. How
krok68 [10]

Answer:

The organism died 35900 years ago

Explanation:

  • Half life C-14 is 5730 years.
  • For decay of radioactive nuclides: \frac{N}{N_{0}}=(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}
  • \frac{N}{N_{0}} is the fraction of radioactive nuclide remain present after t time and t_{\frac{1}{2}} is the half-life of radioactive nuclide
  • Here \frac{N}{N_{0}} is 0.013 and t_{\frac{1}{2}} is 5730 yeras

Plug-in all the values in the above equation:

0.013=(\frac{1}{2})^{\frac{t}{5730years}}

So, t = 35900 years

Hence the organism died 35900 years ago

4 0
3 years ago
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