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jenyasd209 [6]
3 years ago
9

.Loggers cut down 2 identical trees. One tree was cut down with a hand saw and one was cut down with an electric saw. Which acti

vity involved more work? Which one involved more power?
Physics
1 answer:
Advocard [28]3 years ago
6 0
The hand saw involved more work and the electric saw involved more power.
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In fission processes, which of the following statements is true? The total number of protons and the total number of neutrons bo
Amiraneli [1.4K]

Answer: A. The total number of protons and the total number of neutrons both remain the same.

Explanation:

Nuclear fission is the process in which a large nucleus splits into two smaller nuclei with the release of energy. In other words, fission is the process in which a nucleus is divided into two or more fragments, and neutrons and energy are released.

7 0
4 years ago
a trcuk weighs four times as much as a stationary car. if teh truck coasts into the car at 12 km/s and they stick toegther, what
Andrews [41]

Answer:

  v=9.6 km/s

Explanation:

Given that

The mass of the car =  m

The mass of the truck = 4 m

The velocity of the truck ,u= 12 km/s

The final velocity when they stick = v

If there is no any external force on the system  then the total linear momentum of the system will be conserve.

Pi = Pf

m x 0 + 4 m x 12 = (m + 4 m) x v

0 + 48 m = 5 m v

5  v  = 48

v=\dfrac{48}{5}\ km/s

v=9.6 km/s

Therefore the final velocity will be 9.6 km/s.

3 0
3 years ago
A group of science and engineering students embarks on a quest to make an electrostatic projectile launcher. For their first tri
vekshin1

Electric charge on the plastic cube: 1.3\cdot 10^{-7}C

Explanation:

The electric potential around a charged sphere (such as the Van der Graaf) generator is given by

V(r)=\frac{kQ}{r}

where

k is the Coulomb's constant

Q is the charge on the sphere

r is the distance from the centre of the sphere

Here we have:

V = 200,000 V on the surface of the sphere, so at r = 12.0 cm

We need to find the voltage V' at 2.0 cm from the edge of the sphere, so at

r' = 12.0 + 2.0 = 14.0 cm

Since the voltage is inversely proportional to r, we can use:

Vr=V'r'\\V'=\frac{Vr}{r'}=\frac{(200,000)(12.0)}{14.0}=171,429 V

This is the potential at the location of the plastic cube.

Now we can use the law of conservation of energy, which states that the initial electric potential energy of the cube is totally converted into kinetic energy when the plastic cube is at infinite distance from the generator. So we can write:

qV' = \frac{1}{2}mv^2

where:

q is the charge on the plastic cube

V' is the potential at the location of the cube

m = 5.0 g = 0.005 kg is the mass of the cube

v = 3.0 m/s is the final speed of the cube

Solving for q, we find the charge on the cube:

q=\frac{mv^2}{2V'}=\frac{(0.005)(3.0)^2}{2(171,429)}=1.3\cdot 10^{-7}C

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

7 0
3 years ago
Question 7 of 10<br> What is cos(22")?<br> O A. 0.93<br> B. 0.22<br> C. 0.37<br> O D. 0.40
Goshia [24]

Answer:

c

Explanation:

3 0
3 years ago
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What is the Potential Energy of ball 1??
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GPE= height x mass x gravitational field strength 
5 x 10 x 9,8=490J
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4 years ago
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