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Ivenika [448]
4 years ago
6

A body of mass 2.78 kg is pushed straight upward by a 31.3 N vertical force. What is its acceleration (in m/s2)

Physics
1 answer:
Bingel [31]4 years ago
8 0

To solve this problem we will apply the concepts related to Newton's second law for which the product of mass and acceleration is defined as the force applied to an object. Mathematically this is,

F_{net} = ma \rightarrow a = \frac{F_{net}}{m}

Here,

F_{net} = Net external Force

m = Mass of the body

a = Acceleration

The net force on the body would be given by the difference between the ascending force and the weight, therefore,

F_{net} = F-W

Here,

F = Upward Force

W = Weight

The Weight is,

W = (2.78kg)(9.81m/s^2)

W = 27.27N

Then the F_{net} is

F_{net} = 31.3-27.27

F_{net} = 4.03N

Finally replacing at the first equation we have,

a = \frac{4.03N}{2.78kg}

a = 1.44m/s^2

Therefore the acceleration of the stone is 1.44m/s^2

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lisabon 2012 [21]

Answer:

1. The length is 8.35m

2. The period on the moon is 14.05 secs

Explanation:

1. Data obtained from the question. This includes the following:

Period (T) = 5.8 secs

Acceleration due to gravity (g) = 9.8 m/s2

Length (L) =...?

The length can be obtained by using the formula given below:

T = 2π√(L/g)

5.8 = 2π√(L/9.8)

Take the square of both side

(5.8)^2 = 4π^2 x L/ 9.8

Cross multiply

4π^2 x L = (5.8)^2 x 9.8

Divide both side by 4π^2

L = (5.8)^2 x 9.8 / 4π^2

L= 8.35 m

2. Data obtained from the question. This includes the following:

Acceleration due to gravity (g) = 1.67 m/s2

Length (L) = 8.35m (the length remains the same)

Period (T) =?

The period can be obtained as follow:

T = 2π√(L/g)

T = 2π√(8.35/1.67)

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4 0
3 years ago
Consider three scenarios in which a particular box moves downward under the pull of gravity :
luda_lava [24]

Answer:

1. True  WA > WB > WC

Explanation:

In this exercise they give work for several different configurations and ask that we show the relationship between them, the best way to do this is to calculate each work separately.

A) Work is the product of force by distance and the cosine of the angle between them

    WA = W h cos 0

   WA = mg h

B) On a ramp without rubbing

     Sin30 = h / L

     L = h / sin 30

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     WB = F L cos 30

     WB = mf (h / sin30) cos 30

     WB = mg h ctan 30

C) Ramp with rubbing

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   N- Wcos30 = 0

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    F = W (sin30 - μ cos30)

   WC = mg (sin30 - μ cos30) h / sin30

   Wc = mg (1 - μ ctan30) h

When we review the affirmation it is the work where there is rubbing is the smallest and the work where it comes in free fall at the maximum

Let's review the claims

1. True The work of gravity is the greatest and the work where there is friction is the least

2 False. The job where there is friction is the least

3 False work with rubbing is the least

4 False work with rubbing is the least

5 0
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