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Evgen [1.6K]
3 years ago
9

Which of the outer planets would you most likely visit? Why? What would you see on your visit?

Physics
2 answers:
Tanzania [10]3 years ago
6 0
I would like to visit Pluto because i want to see what a Dwarf planet would look like, i would like to see what kind of minerals are in the planet its self..


Brainliest answer?

soldier1979 [14.2K]3 years ago
3 0
I would visit Venus. It’s a beautiful planet and it’s the closest to earth. Also because, Venus is the brightest object in the sky after the Sun and the Moon, and sometimes looks like a bright star in the morning or evening sky. The planet is a little smaller than Earth, and is similar to Earth inside. We can't see the surface of Venus from Earth, because it is covered with thick clouds. It’s an interesting planet. Brainliest PLEASE!!!
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If a lever is 10m long and the effort is applied 4m from the fulcrum, what is the MA of the lever?
Marizza181 [45]
We Know: MA = d₁ / d₂
Here, d₁ = 4
d₂ = 10-4 = 6

Substitute their values into the expression:
MA = 4/6
MA = 2/3

So, Your Answer would be 2/3


Hope this helps!
3 0
3 years ago
Learning Goal: To review the concept of conservative forces and to understand that electrostatic forces are, in fact, conservati
CaHeK987 [17]

Explanation:

The electrostatic forces are conservative forces!

The mainly property of the conservative fields is \vec{\nabla} \times \vec E=\vec 0

In spherical coordinates the field's expression is:

\vec E=\frac{Q}{4\pi \epsilon _0 r^2} .\^r

and the curl expression is:

\nabla\times \vec E=\frac{1}{r^2{\sin}\,\theta}\left|\begin{matrix}\hat{r} & r\,\hat{\theta} & r\,{\sin}\,\theta\,\hat{\varphi}  \\& & \\\frac{\partial}{\partial r} & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial \varphi}\\ & & \\E_r & rE_\theta & r{\sin}\,\theta\, E_\varphi\end{matrix}\right|=(0, 0, 0)

to find the expression for the potential function associated:

\vec E=\vec \nabla . V, \Delta V= V_b-V_a=-\int _c \vec E.d\vec l=-\int _c E\^r.dr\^r=-\int _c Edr=\int \limits^a_b \frac{Q}{4\pi \epsilon _0 r^2} dr= \frac{Q}{4\pi \epsilon _0}.(\frac{1}{r}|^b_a)= \frac{Q}{4\pi \epsilon _0}.(\frac{1}{b}-\frac{1}{a})

5 0
3 years ago
Plzzzzzzzzz help me will mark u brainest
Andrew [12]

Answer:

B

Explanation:

acceleration = change in speed / change in time

for 1, speed increases over time, so positive acceleration

for 3, speed decreases over time, so negative acceleration (or deceleration)

5 0
3 years ago
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AlladinOne [14]
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7 0
3 years ago
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Rank the vector combinations on the basis of their magnitude.
melomori [17]

I think this is about the 5th or 6th time I've seen this question
submitted to Brainly.  So far, nobody has yet given us any of
the rest of the question ... the part that tells us something about
the vectors, so that we have some way to know their magnitudes.
So far, nada.

6 0
3 years ago
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