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3 years ago

Which of the outer planets would you most likely visit? Why? What would you see on your visit?

2 answers:

6 0

I would like to visit Pluto because i want to see what a Dwarf planet would look like, i would like to see what kind of minerals are in the planet its self..

Brainliest answer?

soldier1979 [14.2K]3 years ago

3 0

I would visit Venus. It’s a beautiful planet and it’s the closest to earth. Also because, Venus is the brightest object in the sky after the Sun and the Moon, and sometimes looks like a bright star in the morning or evening sky. The planet is a little smaller than Earth, and is similar to Earth inside. We can't see the surface of Venus from Earth, because it is covered with thick clouds. It’s an interesting planet. Brainliest PLEASE!!!

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In most cases, magma differentiation (a.k.a. fractional crystallization produces magma with higher ___________ content than the

Delicious77 [7]

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3 years ago

Select the correct answer.

Alenkasestr [34]

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3 years ago

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Inessa [10]

Answer:

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2 years ago

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Suppose that the acceleration of a model rocket is proportional to the difference between 100 ft/sec and the rocket's velocity.

sp2606 [1]

Answer:

Explanation:

initial velocity, u = 0

final velocity, v = 80 ft/s

acceleration, a = 150 ft/s²

Let the time taken is t.

v = u + at

80 = 0 + 150 x t

t = 0.53 second

3 0

3 years ago

A satellite at a particular point along an elliptical orbit has a gravitational potential energy of 5100 MJ with respect to Eart

serious [3.7K]

To solve this problem we will apply the theorem given in the conservation of energy, by which we have that it is conserved and that in terms of potential and kinetic energy, in their initial moment they must be equal to the final potential and kinetic energy. This is,

$E_{initial} = E_{final}$

$PE_{initial}+KE_{initial} = PE_{final}+KE_{final}$

Replacing the 5100MJ for satellite as initial potential energy, 4200MJ for initial kinetic energy and 5700MJ for final potential energy we have that

$KE_{final} = (PE_{initial}+KE_{initial} )-PE_{final}$

$KE_{final} = (5100+4200)-5700$

$KE_{final} = 3600MJ$

Therefore the final kinetic energy is 3600MJ

5 0

3 years ago