Answer:
33.65°
Explanation:
radius, r = 53.1 m
m = 2.9 Mg = 2.9 x 10^6 g = 2900 kg
v = 67 km/h
convert km/h into m/s
v = 18.61 m/s
Let the angle of banking of road is θ, without friction


tan θ = 0.6655
θ = 33.65°
Thus, the angle of banking of road is 33.65°.
Answer:
Ep = 0.6095 [J]
Explanation:
As defined in the problem statement, potential energy is defined as the product of mass by gravity by height. But first we must convert all the values given to measures of the international system (SI)
g = gravity = 10 [m/s^2]
h = elevation = 40 [ft] = 12.19 [m]
m = mass = 5 [g] = 0.005 [kg]
Ep = potential energy [J]
Ep = 0.005*10*12.19 = 0.6095 [J]
The main cause of the seasons is earths orbit since each time were in a new season the planet is facing the earth a different way which causes winter etc..
A) Vi= 60 m/s
a= -9.81 m/s^2
Vf= 0m/s^2
d=?
Vf^2=Vi^2+2ad
(0m/s)^2=(60m/s)^2+2(-9.81m/s^2)d
0=3600+(-19.62)d
-3600=(-19.62)d
(-3600)/(-19.62)=(-19.62)d/(-19.62)
d=183.5m
c) Vi= 60 m/s
a= -9.81 m/s^2
Vf= 0m/s^2
t=10s
d=?
d=Vi*t+(1/2)a*t^2
d=60m/s(10s)+(1/2)(-9.81m/s^2)(10s)^2
d=600+(-4.905)(100)
d=600+(-490.5)
d=108.5m
Answer:
Attached below
Explanation:
The plot showing the potential as a function of distance from the center of the sphere is attached below
note : The Potential inside the sphere will remain constant as potential remains constant on surface and it start to decrease as 1/r