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77julia77 [94]
3 years ago
10

• Balance this chemical equation.

Chemistry
1 answer:
user100 [1]3 years ago
4 0

Answer:

Explanation:

Chemical equation:

FeCl₃  +  NaOH   →  Fe(OH)₃ + NaCl

Balanced chemical equation:

FeCl₃  +  3NaOH   →  Fe(OH)₃ + 3NaCl

Step 1:

FeCl₃  +  NaOH   →  Fe(OH)₃ + NaCl

Fe = 1                             Fe = 1

Cl =  3                            Cl = 1

Na =  1                            Na =  1

OH = 1                             OH = 3

Step 2:

FeCl₃  +  3NaOH   →  Fe(OH)₃ + NaCl

Fe = 1                              Fe = 1

Cl =  3                             Cl = 1

Na =  3                            Na =  1

OH = 3                             OH = 3

Step 3:

FeCl₃  +  3NaOH   →  Fe(OH)₃ + 3NaCl

Fe = 1                              Fe = 1

Cl =  3                             Cl = 3

Na =  3                            Na =  3

OH = 3                             OH = 3

Now we the equation is completely balanced and follow  the law of conservation of mass because there are equal number of atoms of each elements are present on both side.

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction .

Type of reaction:

It is double displacement reaction.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

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Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.
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Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

 moles HCl = moles KOH \\  \\ cHCl*vHCl=cKOH*vKOH \\  \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}=  541,54mL

So, the required volume of HCl is 541,54 mL

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