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leva [86]
3 years ago
8

Describe the difference between a transverse wave and longitudinal wave. Include the parts that you would find on a transverse w

ave and longitudinal wave. Give an example of each.
PLEASE HELP! ITS A WRITTEN RESPONSE!
Physics
2 answers:
irina1246 [14]3 years ago
7 0

Answer:

A transverse wave is a moving wave in which the current is perpendicular to the direction of the wave or path of propagation. A longitudinal wave are waves in which the displacement of the median is in the direction of the propagation.

Explanation:

hi

spayn [35]3 years ago
6 0
A transverse wave is a moving wave in which the current is perpendicular to the direction of the wave or path of propagation. A longitudinal wave are waves in which the displacement of the median is in the direction of the propagation.
Example:
Transverse- pond ripple
Longitudinal- crest and troff
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I AM TIMED !! 30 POINTS Which is the smallest possible particle of an element?
zimovet [89]

Answer:

atoms

Explanation:

they are the smallest

4 0
3 years ago
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A particle (mass = 5.0 g, charge = 40 mC) moves in a region of space where the electric field is uniform and is given by Ex = –2
taurus [48]

Answer: 40m

Explanation: Distance is a function of speed/ velocity and time.

From the question the velocity along the z axis is given as 20 m/s at t = 0 secs We were ask to calculate the distance travelled when t = 2secs.

Recall that,

Velocity = distance travelled / time

Since we're calculating for distance we make it subject of formula;

Distance travelled = velocity * time

= 20m/s * 2s

= 40meter.

3 0
3 years ago
The magnitude, M, of an earthquake is represented by the equation M=23logEE0 where E is the amount of energy released by the ear
vfiekz [6]

Answer:

The amount of energy released by the earthquake in joules is 4.4×10^12 J.

Explanation:

As, we have given the magnitude,

M = 2/3 Log E/Eo

where E is the amount of energy released by the earthquake in joules and Eo=10^4.4 is the assigned minimal measure released by an earthquake.

As, the magnitude is given which is 5.5 then put it in the above equation,

5.5 = 2/3 Log E/Eo

Log E/Eo = 5.5×3 / 2

Log E/Eo = 8.25

Now, we will find the amount of energy released by an earthquake:

Log E/Eo = 8.25

Taking antilog,

E/Eo = 10^8.25

But Eo is given which is Eo = 10^4.4

E/(10^4.4) = 10^8.25

E = 10^8.25 × 10^4.4

E = 4.4×10^12 J.

8 0
4 years ago
what is the vapor pressure of water if the total vapor pressure is 1.5 atm and the pressure of oxygen is 0.2 atm?
andreyandreev [35.5K]

Since the total pressure of each gas is the sum of the partial pressures of all the individual gases, the vapor pressure of oxygen is  1.3 atm.

From Dalton's law of partial pressure, the total pressure is the sum of the individual partial pressures of the gases;

PT = PA + PB + PC + --------

Given that;

Vapor pressure of oxygen = 0.2 atm

Total pressure = 1.5 atm

Vapor pressure of oxygen = ?

Partial pressure of oxygen =  1.5 atm - 0.2 atm = 1.3 atm

The vapor pressure of oxygen is  1.3 atm.

Learn more: brainly.com/question/2510654

8 0
3 years ago
You overindulged on a delicious dessert, so you plan to work off the extra calories at the gym. To accomplish this, you decide t
iragen [17]

Answer:

17086

Explanation:

We are given that

Weight=5 kg

Distance of elbow from the weight=d=35 cm=\frac{35}{100}=0.35 m

1 m=100 cm

g=9.8m/s^2

Work done  each time on the weight=mgh=5\times 9.8\times 0.35=17.15 J

20%  means 0.20 of food energy=Work done each time on weight

Total work done in each time=\frac{17.15}{0.2}=85.75J

1 food calorie=4186 J

350 food calories=350\times 4186 J

Number of lift needed=\frac{350\times 4186}{85.75}=17086

Hence, you must do 17086 arm raises to work off 350 food calories.

6 0
4 years ago
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