3 years ago

May I get some help please?

Physics

1 answer:

ziro4ka [17]3 years ago

7 0

Arrows point away from both north and south.

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Answer:

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Explanation:

Given data

$m_{app}$ = 4.5 kg

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The true mass of the aluminium is given by

$m_{alu} = \frac{\rho_{alu}m_{app}}{\rho_{alu} -\rho_{air} }$

Put all the values in above equation we get

$m_{alu} = \frac{(2700)(4.5)}{2700-1.29}$

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Therefore the true weight of the aluminium is $m_{alu} =$ 4.5021 kg

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