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MrRa [10]
3 years ago
7

In part A of the experiment you will need to make a 4.80 x 10-4 M KSCN solution starting with a 2.00 x 10-3M KSCN solution. You

will be making up the solution in a 25.00 mL volumetric flask and using 0.5 M HNO3 as the diluent. What volume of 2.00 x 10-3 M KSCN will you need
Chemistry
1 answer:
ryzh [129]3 years ago
7 0

Answer:

Answer to you need to make a 6.00 x 10-4 M KSCN solution starting with a 2.00 x 10-3 M KSCN solution. You will be making up the so. ... X 10-3 M KSCN Solution. You Will Be Making Up The Solution In A 25 ML Volumetric Flask And Using 0.5 M HNO3 As The Diluent. What Volume Of 2.00 X 10-3 M KSCN Will You Need?

Explanation:

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Is magnesium carbonate soluble in water
seropon [69]

Answer:

no it is not, it is only soluable in acid.

5 0
3 years ago
Read 2 more answers
I have an unknown volume of gas at a temperature of 115 K in a container with a pressure of 60 atm. If we increase the temperatu
stepan [7]

Answer:

113.5 L

Explanation:

Use combined gas law and rearrange formula.

- Hope this helps! Please let me know if you need further explanation.

3 0
3 years ago
Indicate whether either an increase or decrease of pressure obtained by changing the volume would increase the amount the produc
vazorg [7]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle:

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On an increase in the volume :

If the volume of the container is increased, the pressure will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where increase in pressure is taking place.And equilibrium will shift in direction where number of gaseous moles are more.

On an decrease in the volume :

If the volume of the container is decreased , the pressure will increase according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decease in pressure is taking place.And equilibrium will shift in direction where number of gaseous moles are less.

a. CO(g) + 2 H_2(g)\rightleftharpoons CH_3OH(g)

On an increase in the volume :

As the number of moles of gas molecules is greater at the reactant side. So, the equilibrium will shift in the left direction. So in order to  increase the amount of product we have to increase the pressure of the reactants molecules decrease the volume.

b.2SO_2(g) +O_2(g) \rightleftharpoons 2SO_3(g)

As the number of moles of gas molecules is greater at the reactant side. So, the equilibrium will shift in the left direction. So in order to  increase the amount of product we have to increase the pressure of the reactants molecules decrease the volume.

c. 2NO_2(g)\rightleftharpoons N_2O_4(g)

As the number of moles of gas molecules is greater at the reactant side. So, the equilibrium will shift in the left direction. So in order to  increase the amount of product we have to increase the pressure of the reactants molecules and decrease the volume .

5 0
3 years ago
At 300 K, the vapor pressure of pure benzene (C6H6) is 0.1355 atm and the vapor pressure of pure n-hexane (C6H14) is 0.2128 atm.
kirill [66]

Answer:

A. 0525.

B. 0.3483 atm.

C. 0.3890.

Explanation:

A.

Molar mass of Benzene =

(12*6) + (1*6)

= 78 g/mol.

Number of moles of Benzene = mass/molar mass

= 50/78

= 0.641 moles.

Molar mass of n-hexane =

(12*6) + (1*14)

= 86 g/mol.

Number of moles of n-hexane = mass/molar mass

= 50/86

= 0.581 moles.

Total moles of the solution = number of moles of Benzene + number of moles of n-hexane

= 0.641 + 0.581

= 1.222 moles

Mole fraction is the number of moles of a particular substance in a solution divided by the total number of moles of substances in the solution.

Mole fraction of Benzene = 0.641/1.222

= 0.525.

B.

Vapour Pressure of a solution is the amount of pressure that the vapour exert on the liquid solvent when they are in equilibrium and at a certain temperature.

Uaing Raouit's law and Dalton's law,

Raoult's law states that the the partial pressure of a solution is directly proportional to the mole fraction of the solute component.

Dalton's law states that the total pressure of a solution is the sum of its individual partial pressure.

Uaing Dalton's law,

Psol = Pbenzene + Pn-hexane

= 0.1355 + 0.2128

= 0.3483 atm

C.

Using Raoult's equation, Mole fraction of Benzene = P°benzene/Psol

= 0.1355/0.3483

= 0.3890

4 0
3 years ago
What two types of evidence are used to classify organisms?
anygoal [31]
Genetics and morphology also the fossil record can be useful too
5 0
3 years ago
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