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MrRa [10]
4 years ago
7

In part A of the experiment you will need to make a 4.80 x 10-4 M KSCN solution starting with a 2.00 x 10-3M KSCN solution. You

will be making up the solution in a 25.00 mL volumetric flask and using 0.5 M HNO3 as the diluent. What volume of 2.00 x 10-3 M KSCN will you need
Chemistry
1 answer:
ryzh [129]4 years ago
7 0

Answer:

Answer to you need to make a 6.00 x 10-4 M KSCN solution starting with a 2.00 x 10-3 M KSCN solution. You will be making up the so. ... X 10-3 M KSCN Solution. You Will Be Making Up The Solution In A 25 ML Volumetric Flask And Using 0.5 M HNO3 As The Diluent. What Volume Of 2.00 X 10-3 M KSCN Will You Need?

Explanation:

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The most reactive metals are located in which area of the periodic table?
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The answer is b.Far left
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3 years ago
Based on the current atomic theory most chemical reaction take place as a result of the interactions of which sub- atomic partic
icang [17]
Electrons, everything is pretty much based around the likeliness of electrons to be swapped or shared between atoms
6 0
3 years ago
Identify the compounds that are soluble in both water and hexane.
dlinn [17]

Answer:

The compound which are boh soluble in water and hexane is

B. Ethanol and 1-propanol  

Explanation:

The compounds ethanol and 1-propanol are soluble in both hexane and water.

It is soluble in water as both  consists of polar end due to hydrogen bonding present in the  -OH functional group.

and both are soluble in hexane as they contain a non polar end and the alliphatic hydrocarbon chain in them.

The solubility of alcohols varies in increasing order as the hydrocarbon chain increases. And becaue of this it becomes more non polar.

Non polar properties decreases for branched molecules.

so, the correct option is ethanol and 1-propanol.

3 0
3 years ago
Points
ExtremeBDS [4]
The answer is D. A compound
6 0
3 years ago
If the mass of the object below is 28g, what is the density of the object below. Units are in cm below. Please round your answer
Murljashka [212]

Answer:

d = 0.93 g/cm³

Explanation:

Given data:

Mass of object = 28 g

Volume of object = 3cm×2cm×5cm

density of object = ?

Solution:

Volume of object = 3cm × 2cm ×5cm

Volume of object = 30 cm³

Density of object:

d = m/v

by putting values,

d = 28 g/ 30 cm³

d = 0.93 g/cm³

3 0
3 years ago
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