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MrRa [10]
4 years ago
7

In part A of the experiment you will need to make a 4.80 x 10-4 M KSCN solution starting with a 2.00 x 10-3M KSCN solution. You

will be making up the solution in a 25.00 mL volumetric flask and using 0.5 M HNO3 as the diluent. What volume of 2.00 x 10-3 M KSCN will you need
Chemistry
1 answer:
ryzh [129]4 years ago
7 0

Answer:

Answer to you need to make a 6.00 x 10-4 M KSCN solution starting with a 2.00 x 10-3 M KSCN solution. You will be making up the so. ... X 10-3 M KSCN Solution. You Will Be Making Up The Solution In A 25 ML Volumetric Flask And Using 0.5 M HNO3 As The Diluent. What Volume Of 2.00 X 10-3 M KSCN Will You Need?

Explanation:

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Answer:

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Explanation:

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3 years ago
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dsp73

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Calculate the enthalpy change, ∆H in kJ, for the reaction H2O(s) → H2(g) + 1/2O2(g). Use the following information: : +279.9 kJ
Delvig [45]

Answer:

+ 291.9 kJ

Solution:

The equation given is as;

H₂O ₍s₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = ?

First, as we know the heat of formation of H₂O ₍l₎ is,

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Now, reversing the equation will reverse the sign of heat as,

H₂O ₍l₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 285.9 kJ

Also, we know that,

H₂O ₍s₎ → H₂O ₍l) ΔH = + 6.0 kJ

Now, adding last two equations,

H₂O ₍l₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 285.9 kJ

H₂O ₍s₎ → H₂O ₍l) ΔH = + 6.0 kJ

-----------------------------------------------------------------------------

H₂O ₍s₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 291.9 kJ

4 0
3 years ago
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anygoal [31]
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7 0
3 years ago
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Answer:

0.052636002587839 moles

Explanation:

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3 years ago
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