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PilotLPTM [1.2K]
4 years ago
11

If the maximum acceleration that is tolerable for passengers in a subway train is 1.39 m/s2 and subway stations are located 780

m apart, what is the maximum speed a subway train can attain between stations
Physics
1 answer:
a_sh-v [17]4 years ago
6 0

Answer:

The maximum speed a subway train can attain between stations is 32.93 m/s.

Explanation:

Given;

maximum tolerable acceleration = 1.39 m/s²

distance between subway train, d = 780 m

The distance available to accelerate between stations = ¹/₂ x 780 m = 390 m

Apply the following kinematic equation to determine the maximum speed;

v² = u² + 2ad

v² = 0 + 2ad

v² = 2(1.39)(390)

v² = 1084.2

v = √1084.2

v = 32.93 m/s

Therefore, the maximum speed a subway train can attain between stations is 32.93 m/s.

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Elina [12.6K]

Answer:

The vertical distance that the ski jumper fell is 417.45 m.

Explanation:

Given;

initial horizontal velocity of the jumper, V_x = 26 m/s

horizontal distance of the jumper, dx = 240 m

The time of the motion is given by;

dx = Vₓt

t = dx / Vₓ

t = 240 / 26

t = 9.23 s

The vertical distance traveled by the diver is given by;

d_y = V_yt + \frac{1}{2}gt^2

initial vertical velocity, V_y, = 0

d_y =  \frac{1}{2}gt^2\\\\d_y = \frac{1}{2}(9.8)(9.23)^2\\\\d_y = 417.45 \ m

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6 0
3 years ago
A force of 960 newtons stretches a spring 4 meters. A mass of 60 kilograms is attached to the end of the spring and is initially
Drupady [299]

Answer:

x(t) = - 6 cos 2t

Explanation:

Force of spring = - kx

k= spring constant

x= distance traveled by compressing

But force = mass × acceleration

==> Force = m × d²x/dt²

===> md²x/dt² = -kx

==> md²x/dt² + kx=0   ------------------------(1)

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ignoring -ve sign k= 240 N/m

Put given data in eq (1)

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General solution for this differential eq is;

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Now initially

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put t =0 and dx/dt = v(0) = -6 we get;

-2A sin 2(0)+2Bcos(0) =-6

==> 2B = -6

B= -3

Putting B = 3 in eq (2) and ignoring first term (because it is not possible to find value of A with given initial conditions) - we get

x(t) = - 6 cos 2t

==>  

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