<span>Mass percent of KCl = 5.7%
So the Mass percent of water = 100 - 5.7 = 94.3%
KCl mixed in 1000 grams of water = (5.7 / 94.3) x 1000 = 60.44 grams
Calculating the moles of KCl = mass of KCL / molecular weight = 60.44 / (K (39.1) + Cl(35.5)) = 60.44 / 74.6 = 0.81 moles and KCl release twice the moles, so 2 x 0.81 = 1.62 moles
So the molarity M = 1.62, Kf is the freezing point depression constant of the solvent, here water
So Kf = 1.86 °C/m Freezing point temperature dT = Kf x M = 1.86 x 1.62 = 3.01 C</span>
5.7% KCl is 94.3 % water. Therefore, for 1000 g of water the mass of KCl will be (1000× 5.7)/94.3 = 60.445 grams. 1 mole of KCl is equal to 74.55 g, therefore, 60.445 g will be 60.445/74.55 = 0.8108 mole of KCl Hence, 0.8108 moles of KCl should release twice that number of moles 1.6216 moles ions. Having 1.6216 moles of KCl ions dissolved in 1000g of water, gives us 1.6216 molar if solution. Using the freezing point depression constant of water. dT = Kf (molarity) dT = (1.86 C/ molar) (1.6216 m) dT = 3.016 C drop in freezing point Therefore, it should freeze at - 3.016 Celsius
This is false. They were both chemists and they made many discoveries such as realizing that charcoal and diamond are different forms of the same element and proposing an atomic theory, but they never tried to turn diamonds to gold.
