Answer: 800 mL of methyl alcohol should be added to 200 ml of water to make this solution.
Explanation:
Volume of the methyl alcohol = x
Volume of water = y = 200 mL
Volume of the solution ,V = x + y
Volume percentage of solution = 80%
x = 800 mL
800 mL of methyl alcohol should be added to 200 ml of water to make this solution.
Answer:
0.2M NaOh
Explanation:
there are 0.2 mol of NaOH in 8.0 g. (8.0/40) =0.2. Molarity = mol/L = 0.2M.
Answer:
Question 2: Na3PO4, KOH; Question 3: Na3PO4, KOH
Explanation:
Question 2
The reactants in a chemical equation are the species on the left side of the reaction arrow.
Thus the reactants are Na3PO4, KOH (sodium phosphate and potassium hydroxide).
Question 3.
The products in a chemical equation are the species on the right side of the reaction arrow.
Thus the products are NaOH, K3PO4 (sodium hydroxide and potassium phosphate).
First we must write a balanced chemical equation for this reaction

The mole ratio for the reaction between
and
is 1:2. This means 1 moles of
will neutralize 2 moles
. Now we find the moles of each reactant based on the mass and molar mass.



The
was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.