From the reaction of ammonia and sulfuric acid in aqueous solution
2nh3(aq)+h2so4(aq)<span>→</span> (NH4)2SO4 + H2O
will be formed.Sulfuric acid is diprotic so is able to give up 2 H+ ions.
It is an acid-base neutralisation reaction forming ammonium sulphate as the salt.
2NH3 with H2SO4 reacts in a neutralization reaction to form salt water, with ammonium sulphate left behind to crystallize after evaporation.
Answer: The concentration of
ions in vinegar is 0.001 M.
Explanation:
Given: pH = 3.0
pH is the negative logarithm of concentration of hydrogen ion.
The expression for pH is as follows.
![pH = - log [H^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D)
Substitute the value into above expression as follows.
![pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D%5C%5C3.0%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D%5C%5Cconc.%20of%20H%5E%7B%2B%7D%20%3D%20antilog%20%28-%203.0%29%5C%5C%3D%200.001%20M)
Thus, we can conclude that the concentration of
ions in vinegar is 0.001 M.
A nitrogen atoms can make 3 covalent bonds because it has three unpaired electrons