All categories

2 years ago

Differ B/w reducing and oxidizing smog?

Chemistry

1 answer:

aleksklad [387]2 years ago

6 0

Answer:

Smog can be classified as two types. They are

Oxidizing smog

Reducing smog

Oxidizing smog:

The smog which has the property of high concentration of oxidizing agents is known as oxidizing smog. Oxidizing smog can also known as photochemical smog.

Example: Ozone.

Reducing smog:

The smog which has high concentration of sulfur Dioxide is known as reducing smog.Photochemical smog which is very dangerous is called oxidizing smog because it consists of the oxidizing agent ozone.......the other one is reducing smog which consists of reducing agent sulphurdioxide.

You might be interested in

If 0.400 moles CO and 0.400 moles O2 completely react how many grams of CO2 are produces?

True [87]

If 0.400 moles CO and 0.400 moles O2 completely react, 17.604 grams of CO2 would be produced.

First, let us look at the balanced equation of reaction:

$2CO + O_2 ---> 2CO_2$

According to the equation, the mole ratio of CO and O2 is 2:1. But in reality, the mole ratio supplied is 1:1. Thus, CO is the limiting reactant while O2 is in excess.

Also from the equation, the ratio of CO consumed to that of CO2 produced is 1:1. Thus, 0.400 moles of CO2 would also be produced from 0.400 moles of CO.

Recall that: mole = mass/molar mass

Therefore, the mass in grams of CO2 that would be produced from 0.400 moles can be calculated as:

Mass = mole x molar mass

= 0.400 x 44.01

= 17.604 grams

More on calculating mass from number of moles can be found here: brainly.com/question/12513822

7 0

2 years ago

EXTRA CREDIT

marin [14]

Answer:

$\huge\boxed{\sf 36\ H\ atoms}$

Explanation:

Molecular formula from Glucose:

C₆H₁₂O₆

3 moles of Glucose:

3C₆H₁₂O₆

In 1 mole of Glucose, there are 12 hydrogen atoms.

In 3 moles:

= 12 × 3

= 36 H atoms

$\rule[225]{225}{2}$

5 0

2 years ago

A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr

sertanlavr [38]

Answer: The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.947 atm

$P_2$ = final pressure of gas = 0.987 atm

$V_1$ = initial volume of gas = 150 ml

$V_2$ = final volume of gas = 144 ml

$T_1$ = initial temperature of gas = $25^0C=(25+273.15)K=298.15K$

$T_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}$

$T_2=298.31K=(298.31-273.15)^0C=25.16^0C$

The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

4 0

3 years ago

What’s the most density thing out of

Oksanka [162]

Answer:

Iron is the densest out of the given options.

Explanation:

Oxygen

1.429 g/L

Water

1000 g/L

Hydrogen Peroxide

1450 g/L

Iron

7874 g/L

Iron Oxide

5240 g/L

7 0

3 years ago

The relatively high boiling point of water is due to water having

Verizon [17]

The answer should be hydrogen bonding. Water only has oxygen and hydrogen in it, which are both nonmetals, so you know the answer cannot be metallic or ionic. It also cannot be nonpolar because the electronegativity of the oxygens will make the molecule polar. You can also know it is hydrogen bonding because it can only take place when a hydrogen is attached to an oxygen, fluorine, or nitrogen. These bonds are very strong attractions, so the molecules are extremely hard to pull apart, creating a high boiling point. Hope that helps!

3 0

3 years ago