All categories

3 years ago

Differ B/w reducing and oxidizing smog?

Chemistry

1 answer:

aleksklad [387]3 years ago

6 0

Answer:

Smog can be classified as two types. They are

Oxidizing smog

Reducing smog

Oxidizing smog:

The smog which has the property of high concentration of oxidizing agents is known as oxidizing smog. Oxidizing smog can also known as photochemical smog.

Example: Ozone.

Reducing smog:

The smog which has high concentration of sulfur Dioxide is known as reducing smog.Photochemical smog which is very dangerous is called oxidizing smog because it consists of the oxidizing agent ozone.......the other one is reducing smog which consists of reducing agent sulphurdioxide.

You might be interested in

A sample of helium gas has a pressure of 1.20 atm at 22.0 C. At what Celsius temperature will the helium reach a pressure of 2.0

Anarel [89]

Answer: 36.6°C

Explanation:

Given that,

initial pressure of helium (P1) = 1.20 atm

Initial temperature (T1) = 22.0°C

Final temperature (T2) = ?

Final pressure of helium (P2) = 2.00 atm

Since pressure and temperature are given while volume is constant, apply the formula for pressure's law

P1/T1= P2/T2

1.20 atm / 22.0°C = 2.00 atm / T2

Cross multiply

1.20 atm•T2= 2.00 atm•22°C

1.20 atm•T2= 44 atm•°C

Divide both sides by 1.20 atm

1.20 atm•T2/1.20 atm = 44 atm•°C/1.20 atm

T2 = 36.6°C

8 0

4 years ago

An atom that has 13 protons and 15 neutrons is an isotope of the element

kondaur [170]

That would be the element aluminum.

5 0

3 years ago

Which organic molecule is found in the chromatin of cells?

zhenek [66]

Truendkeidiizjfjrnbnfjfiiciuejjcjd

7 0

3 years ago

What is change in atomic number when an atom emits positron?

USPshnik [31]

When a nucleus emits a positron, its atomic number is lowered by one but its mass number stays the same.

8 0

4 years ago

Read 2 more answers

12 is produced by the reaction of 0.5235 mol of CuCl2 according to the following equation: 2CuCl2 +4K1—2Cul + 4KCI + 12. What is

Keith_Richards [23]

Answer:

The mass of I₂ produced is 66.43 g.

Explanation:

In a stoichiometry exercise we follow a series of steps.

Step 1: Write the balanced equation

2 CuCl₂ + 4 KI ⇄ 2 CuI + 4 KCl + I₂

Step 2: Look for the relationship between the data we have and the one we are looking for

According to the balanced equation, when 2 moles of CuCl₂ react 1 mole of I₂ is formed. This is the first relation. Secondly, we know that the molar mass of 253.80 g/mol, that is, every mole of I₂ has a mass of 253.80 g. This is the second relation.

Step 3: Apply relations to the data we have

$0.5235mol(CuCl_{2}).\frac{1mol(I_{2})}{2mol(CuCl_{2})} .\frac{253.80g(I_{2})}{1mol(I_{2})} =66.43g(I_{2})$

7 0

3 years ago