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Ede4ka [16]
2 years ago
14

If 16.4 grams of copper (II) bromide react with 22.7 grams of sodium chloride, how many grams of sodium bromide are formed?

Chemistry
1 answer:
fomenos2 years ago
4 0

The amount of sodium bromide that would be formed from the reaction will be 7.5524 grams

<h3>Stoichiometric calculation</h3>

Looking at the equation of the reaction:

CuBr_2 + 2NaCl --- > CuCl_2 + 2NaBr

The mole ratio of CuBr2 and NaCl is 1:2.

Mole of 16.4 grams of CuBr2 = 16.4/223.37

                                                 = 0.0734 moles

Mole of 22.7 grams of NaCl = 22.7/58.44

                                                 = 0.3884 moles

Equivalent mole of NaCl = 0.1468 moles

Thus, NaCl is in excess while CuBr2 is limiting.

Mole ratio of CuBr2 and NaBr = 1:1

Mass of 0.0734 mole NaBr = 0.0734 x 102.894

                                              = 7.5524 grams

More on stoichiometric calculation can be found here: brainly.com/question/8062886

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Read 2 more answers
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GenaCL600 [577]

Answer:

The correct options are:

1) Pure chemical substance

2) Element.

Explanation:

each of the term is explained below:

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2) False by definition of mixture.

3) false by definition of mixture.

4) <u>Solution:</u> Tungsten in a filament is in solid form hence solution is incorrect.

5) Since it is given in the question itself that the sample is pure hence option 'E' is correct as chemical substance is a pure substance that has a homogeneous composition and the sample in the question is given as pure.

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8 0
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alex41 [277]

Answer:

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The correct answer is - There is no shift in the state.

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where Q, is the reaction Quotient

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