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Charra [1.4K]
2 years ago
14

If I throw a 10 kg ball with a force of 60 N, what will the ball's acceleration be?

Chemistry
1 answer:
Nata [24]2 years ago
8 0

Answer:

6

Explanation:

f=ma (from Newton's second law of motion)

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PLEASE HELP URGENT!!!! ( photo included)
Aliun [14]
Water, lower, and I'm not too sure for the third one... sorry.
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3 years ago
Rutherford proposed that atoms have positive nuclei. Which statement correctly describes the nucleus of an atom?
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3 years ago
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Compound element ratio of 1:2:6<br> Ba(NO3)2+Na2SO4
Karo-lina-s [1.5K]

1:2:6? Ba(NO3)2 +Na2SO4 -----> BaSO4 + 2NaNO3

Ba(NO3)2

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NaNO 3

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3 years ago
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Why is it important to use chemicals of high quality (purity) and exact(correct) concentrations in experiments?​
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It is important to use chemicals of high quality and correct concentrations in experiment so that we can obtain the predictable result in an experiment

Purity of substances/chemicals is very important when performing experiments in the laboratories, because it plays an important role in the determination of the chemical properties of  substances which will have a direct effect on the result obtained from the experiment. likewise using the correct concentration of reagents

During experiments to obtain the best/predictable result in an experiment it is of best practice to make use of chemicals of high quality and also at the exact(needed) concentrations, that way the predictable result of the experiment will be obtained.

Learn more : brainly.com/question/8684258

6 0
2 years ago
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n a gas-phase equilibrium mixture of SbCl5, SbCl3, and Cl2 at 500 K, pSbCl5 = 0.17 bar and pSbCl3 = 0.22 bar. Calculate the equi
Lorico [155]

Answer:

2.7 × 10⁻⁴ bar

Explanation:

Let's consider the following reaction at equilibrium.

SbCl₅(g) ⇄ SbCl₃(g) + Cl₂(g)

The pressure equilibrium constant (Kp) is 3.5 × 10⁻⁴. We can use these data and the partial pressures at equilibrium of SbCl₅ and SbCl₃, to find the partial pressure at equilibrium of Cl₂.

Kp = pSbCl₃ × pCl₂ / pSbCl₅

pCl₂ = Kp × pSbCl₅ / pSbCl₃

pCl₂ = 3.5 × 10⁻⁴ × 0.17 / 0.22

pCl₂ = 2.7 × 10⁻⁴ bar

7 0
3 years ago
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