Answer:
The concentration of the newly prepared solution is 8 * 10^-5 M
Explanation:
The most common way to solve this problem is to use the following formula
c1*V1 = c2*V2
with c1 = 1 * 10^-3 M
with V1 = 20 mL = 0.02 L
with c2 = TO BE DETERMINED
with V2 = 250 mL = O.250 L
10^-3 * 0.02 L = c2 * 0.250L
0.00002 = c2 * 0.250L
c2 = 0.00002 / 0.250 L
c2 = 0.00008 M = 8 * 10^-5 M
The concentration of the newly prepared solution is 8 * 10^-5 M
The product when an unsaturated hydrocarbon undergoes complete addition would be a saturated molecule. These saturated hydrocarbons becomes Alkanes where these molecules are only single-bonded in contrary to unsaturated hydrocarbons which have multiple bonds between atoms.
Answer:
The rate of forward reaction increases.
Explanation:
- Le Châtelier's principle states that <em>when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>
Increasing the volume of oxygen:
will increase the concentration of oxygen (reactants), so the equilibrium will be shifted to the right side (products side) to suppress the effect of increasing the volume of oxygen.
<em>So, the right choice is: The rate of forward reaction increases.
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Hydroboration addition of borane to a compound across the double bond.
<h3>What is hydroboration?</h3>
The reaction that is called hydroboration could be carried out with an alkene or an alkyne as the case maybe. In each case, the reaction involves the addition of borane to a compound across the double bond. The reaction could further proceed to produce an alkanol.
Let us restate that like most of the organic reactions, this reaction occurs in a sequence of steps and each step of the reaction has a way of bringing us closer to the end product of the entire steps of the reaction take in proper order
As shown in the image attached to this answer, the reaction was carried out in DMS in order to stabilize the borane. We have shown the borane to be a reactant as it adds across the double bond to yield the product.
Learn more about hydroboration:brainly.com/question/11655454
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Answer:
It results from microscopic bumps and ridges
It causes a change in motion
It is opposite to the direction of the motion.
It is parallel to the surfaces that rub together.
Explanation:
