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aleksley [76]
3 years ago
12

Which statements describe friction? Select four options.

Chemistry
2 answers:
Aleks04 [339]3 years ago
8 0

Answer:

It results from microscopic bumps and ridges

It causes a change in motion

It is opposite to the direction of the motion.

It is parallel to the surfaces that rub together.

Explanation:

joja [24]3 years ago
4 0

<u>Answer:</u>

Option (D) &(E)

It is opposite to the direction of the motion and  it is parallel to the surfaces that rub together

<u>Explanation:</u>

One of the simplest features of friction is that it is parallel to the inter-system touch layer and always in a position which contradicts the system's movement or attempted motion related to each other.

When two structures are in contact with each other, so kinetic friction takes place between them. For instance, friction slows down a slipping hockey puck on ice. Yet static friction will work between them when objects are at rest; static friction will be typically greater than kinetic friction between the bodies.

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What colour is litmus in a solution of pH 4?
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How many moles of Ag will be produced from 16.0 g of Cu, assuming AgNO3 is available in excess
madreJ [45]

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Explanation:

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How can I explain that orange juice is a homogeneous mixture ?
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A concentration cell consisting of two hydrogen electrodes (PH2 = 1 atm), where the cathode is a standard hydrogen electrode and
Lunna [17]

The pH of the unknown solution is 3.07.

<u>Explanation:</u>

<u>1.Find the cell potential as a function of pH</u>

From the Nernst Equation:

Ecell=E∘cell−RT /zF × lnQ

where

R denotes the Universal Gas Constant

T denotes the temperature

z denotes the moles of electrons transferred per mole of hydrogen

F denotes the Faraday constant

Q denotes the reaction quotient

Substitute the values,

E∘cell=0   lnQ=2.303logQ

E0cell=−2.30/RT /zF × log Q

Solving the equation,

<u>2. Find the Q  value</u>

Q=[H+]2prod pH₂, product/ [H+]2reactpH₂, reactant

Q=[H+]^2×1/1×1=[H+]2

Taking the log

logQ= log[H+]^2=2log[H+]=-2pH

From the formula,

Ecell=−2.303RT /zF× logQ

E cell= 2.303 × 8.314 CK mol (inverse)  × 298.15

K × 2pH /2×96 485  C⋅mol

( inverse)

E cell= 0.0592 V × pH

<u>3. Finding the pH value</u>

E cell= 0.0592 V × pH

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pH=3.07

The pH of the unknown solution is 3.07.

7 0
3 years ago
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