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FinnZ [79.3K]
3 years ago
13

Is this statement true or false? The littoral zone is exposed to air.

Physics
1 answer:
Nezavi [6.7K]3 years ago
3 0
It is indeed true. the litoral zone is exposed to air.
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A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force)
katen-ka-za [31]

Answer:

Velocity will be equal to 7.31 m/sec

Explanation:

We have given mass of the student m = 61 kg

Height of the water slide h = 12.3 m

Acceleration due to gravity g=9.8m/sec^2

Potential energy is equal to U=mgh=61\times 9.8\times 12.3=7352.94J

Work done due to friction = -5800 J

So energy remained = 7352.94-5800 = 1552.94 J

This energy will be equal to kinetic energy

So \frac{1}{2}mv^2=1552.94

\frac{1}{2}\times 61\times v^2=1552.94

v^2=50.91

v = 7.13 m/sec

7 0
3 years ago
Wagon wheel. While working on your latest novel about settlers crossing the Great Plains in a wagon train, you get into an argum
OverLord2011 [107]

Answer:

I = 16.7kgm²

Explanation:

Since, Torque is given by,

\tau = F*r = I*\alpha

here, I = Moment of inertia = ??

\alpha = angular acceleration of wheel = a/r

F = tangential tension acting on the wheel = T

a = acceleration of bag of sand = 2.95 m/s^2

r = radius of wheel = d/2 = 120/2 = 60 cm = 0.60 m

from force balance on sand bag,

mg - T = m*a

T = m*(g-a)

m = mass of sand bag = 20 kg

So, I = T*r/\alpha = m*(g-a)*r/(a/r)

Using known values:

I = 20*(9.81 - 2.95)*0.60/(2.95/0.60) = 16.74

I = 16.7 kgm² = Moment of inertia of wheel experimentally

also, Moment of inertia of wheel theoretically(I') = M*r²

given, M = mass of wheel = 70 kg

I' = 70*0.60²= 25.2 kgm² = Moment of inertia of wheel theoretically

7 0
3 years ago
Express the vector R<br> B<br> in terms of A, B, C, and Ď, the edges of a<br> parallelogram.
Vadim26 [7]

Answer:

R=0.5B+0.5C+2A+D

Explanation:

By the triangular law of vector addition

vector R= vector B- vector D

As A,B,C,D are edges of the parallelogram,

A is parallel to D but opposite in direction.

Therefore

A = (-D);A//D;

2A=-2D

B is parallel to C and in same direction.

B//C\\B=C\\

0.5B=0.5C\\

R= B-D;\\R= 0.5B+0.5B-D;\\R=0.5B+0.5C-D;\\R=0.5B+0.5C-2D+D;\\R=0.5B+0.5C+2A+D;

7 0
3 years ago
Which of the following describes the normal shape of a DNA molecule?
Rudiy27

Answer:

A. Two strands of nucleotides bonded together at their bases,

twisting to form a double helix

Explanation:

Hope this helps! Can I have brainliest?

5 0
3 years ago
A cart starts at x = +6.0 m and travels towards the origin with a constant speed of 2.0 m/s. What is it the exact cart position
Ira Lisetskai [31]

Answer:

At the origin (x' = 0 m)

Explanation:

Note: From the question, when the cart travels towards the origin, the magnitude of its exact position reduces with time.

The formula of speed is given as

S = d/t................. Equation 1

Where S = speed of the cart, d = distance covered by the cart over a certain time. t = time taken to cover the distance.

make d the subject of the equation,

d = St ................. Equation 2

Given: S = 2.0 m/s, t = 3.0 s

Substitute into equation 2

d = 2(3)

d = 6 m.

From the above, the cart covered a distance of 6 m in 3 s.

The exact position of the cart = Initial position-distance covered

x' = x-d............ Equation 3

Where x' = exact position of the cart 3 s later, x = initial position of the cart, d = distance covered by the cart in 3.0 s.

Given: x = +6.0 m, d = 6 m.

Substitute into equation 3

x' = +6-6

x' = 0 m.

Hence the cart will be at 0 m (origin) 3 s later

5 0
3 years ago
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