Answer:
The correct option is;
B. Subtract vectors A from C; 
= 12 N
Explanation:
The given parameters are;
The weight of the dresser = 250 N
The force applied by the man = 20 N = C
The frictional force provided by the carpet = 8 N = The component of the weight resisting motion = A
Therefore, the net force tending to put the dresser in motion, , is given as follows;
= The force applied by the man, C - The frictional force provided by the carpet which is the component of the weight resisting motion, A
= C - A = 20 N - 8 N = 12 N
= 12 N
The resulting net force, = 12 N.
Answer:
False.
Explanation:
Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.
Answer:
0.13 seconds
Explanation:
Since 1 Km = 0.621 miles
3.84 x 105 km = 3.84 x 105 × 0.621 = 23846.4 miles
Speed = distance/time
time= distance/speed
Time= 23846.4/186,000
Time= 0.13 seconds
-- Whether an object floats or sinks in water depends on whether its density is more or less than the density of water.
-- The density of the rock didn't change when she threw it into the lake.
-- The density of the water didn't change when she threw the rock into the lake.
-- The density of anything never depends on how much of it you have.
-- If the rock sank in two ounces of water, it'll sink in a billion gallons of water.
-- Choose ' <em>A </em>' .
Answer:
The moment of inertia will be increased by a factor of 1575
Explanation:
Let the moment of inertia of a wheel be given as;
where;
I is the moment of inertia of the wheel
m is mass of the wheel
r is radius of the wheel
when the mass is increased by a factor of 7 and the radius is increased by a factor of 15
![I_1 = \frac{1}{2}mr^2\\ \\I_2 = \frac{1}{2}(7m)(15r)^2\\\\I_2 = \frac{1}{2}(7m)(225r^2)\\\\I_2 = 7\times 225[\frac{1}{2}(mr^2)]\\\\I_2 = 1575[\frac{1}{2}(mr^2)]\\\\Recall, \frac{1}{2}(mr^2) = I_1 \\\\I_2 = 1575 I_1](https://tex.z-dn.net/?f=I_1%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmr%5E2%5C%5C%20%5C%5CI_2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%287m%29%2815r%29%5E2%5C%5C%5C%5CI_2%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%287m%29%28225r%5E2%29%5C%5C%5C%5CI_2%20%3D%207%5Ctimes%20225%5B%5Cfrac%7B1%7D%7B2%7D%28mr%5E2%29%5D%5C%5C%5C%5CI_2%20%3D%201575%5B%5Cfrac%7B1%7D%7B2%7D%28mr%5E2%29%5D%5C%5C%5C%5CRecall%2C%20%5Cfrac%7B1%7D%7B2%7D%28mr%5E2%29%20%3D%20I_1%20%5C%5C%5C%5CI_2%20%3D%201575%20I_1)
Thus, the moment of inertia will be increased by a factor of 1575
