Answer:
(a) 0.061 m/s
(b) 0.103 m/s
Explanation:
From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum
Momentum, p=mv where m is the mass and v is the velocity
where 
is the common velocity, 
is the velocity of the ball 
and 
are masses of the ball and person respectively
Substituting the given values then
(b)
Momentum, p=mv where m is the mass and v is the velocity
is the velocity of the ball , 
is the velocity of ball afterwards and 
is your speed, and are masses of the ball and person respectively. Since it bounces back, we give it a negative value hence
Answer:
h = 5.05 m
Explanation:
given,
mass of pole vaulter, m = 64 Kg
speed of the vaulter,V = 10.2 m/s
horizontal component of velocity in air, v = 1 m/s
height of the jump,h = ?
using energy conservation
initial height of the vaulter is equal to zero.
h = 5.05 m
height of the jump is equal to 5.05 m.
Answer:
kinetic is the stored energy being released from being dormant
Explanation:
Answer:
It's Option D
Explanation:
Red line bounces off left side of black line.
Answer:
Explanation:
Mass of bullet m = .03 kg
Mass of wooden block M = 0.5 kg
Since the center of mass of the wooden block with the bullet in it travels up a distance of 0.60 m before reaching its maximum height
Velocity of wooden block + bullet just after impact = √2gH
=√(2 x 9.8 x 0.6)
= 3.43 m / s
Let the launch velocity of bullet be v₁
If v₂ be the velocity with which bullet hits the block
Applying law of conservation of momentum
.03 x v₂ = .530 x 3.43
v₂ = 60.6 m /s
if v₁ be initial velocity
v₂² = v₁² - 2 gh
v₁² = v₂² + 2 gh
= 60.6 ² + 2 x 9.8 x 0.4
v₁ = 60.65 m /s this is launch speed.
b )
Initial kinetic energy of bullet
= 1/2 m v²
= .5 x .03 x 3680
= 55 J
Potential energy of bullet + block = 0
Total energy = 5 J
c)
Kinetic energy of bullet block system
1/2 m v²
= .5 x .53 x 3.43
= 3.11 J
d )
Loss of energy in the impact = Total mechanical energy lost from beginning to end?
3.11 J - 5
= 1.89 J
