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SashulF [63]
3 years ago
6

Given: G = 6.67259 × 10−11 N m2 /kg2

Physics
1 answer:
8_murik_8 [283]3 years ago
8 0

Answer:

Work done W 2.938*10^9 J

Explanation:

given data:

mass m = 944 Kg

Mass of moon M = 7*10^22 Kg

Radius of the moon R = 1.5*10^6 m

gravitational constant G = 6.67*10^{-11} Nm^2/Kg^2

we know that work done is given as

Work done W = \frac{GMm}{R}

                      = \frac{6.67*10^{-11}*7*10^{22}*944}{1.5*10^6 m}

                      = 2.938*10^9 J

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A 2 N and an 8 N force pull on an object to the right and a 4 N force pulls on the same object to the left. If the object has a
Elden [556K]

Answer:

a = 12 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

ΣF = sum of forces acting on a body [N] (units of Newtons)

m = mass = 0.5 [kg]

a = acceleration [m/s²]

Let's take the direction of positive forces to the right and negative forces directed to the left

2 + 8 - 4 = 0.5*a

6 = 0.5*a

a = 12 [m/s²]

7 0
3 years ago
A force is described by its BLANK and by the direction in which it acts
Andre45 [30]
Strength/magnitude would both work
3 0
3 years ago
What happens to the temperature of a substance when it is changing state of matter?
noname [10]
Solid substances have molecules held tightly and close together
Liquid substances have molecules moving loosely
Gaseous molecules are moving completely freely

As moleclues get further apart, i.e. As a substance changes state from solid to liquid to gas, molecules gain kinetic energy and vibrate/move more. This means they gain heat energy (the averge energy a substance has) so the temperature increases

Substances exist in different states at different temperatures and different substances will exist in different states at the same temperature. This is to do with the forces between molecules and how much heat (energy) is required to break them
5 0
3 years ago
two object gravitationally attract with a force of 20N.if the distance between the two object centers is doubled, then what is t
Usimov [2.4K]
Gravity decreases with the square of the distance, so the new force is (20)/(2*2) = 5N.
8 0
3 years ago
An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the
poizon [28]

Answer:

The value is A  =  0.014 \  m

Explanation:

From the question we are told that

    The mass of the object is  m  =  2.0 \  kg

    The unstressed length of the string is  l  =  0.08 \  m

    The length of the spring when it is  at equilibrium is  l_e = 5.9 \  cm  =  0.059 \  m

      The initial speed (maximum speed)of the spring when given a downward blow v  =  0.30 \  m/s

Generally the maximum speed  of the spring  is mathematically represented as

           u =  A *  w

Here A is maximum height above the floor (i.e the maximum amplitude)

            and w is the angular frequency which is mathematically represented as

       w = \sqrt{\frac{k}{m} }

So

        u =  A *   \sqrt{\frac{k}{m} }

=>      A  =  u *   \sqrt{\frac{m}{k} }

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

           b  =  l -l_e

=>         b  = 0.08 - 0.05 9

=>         b  = 0.021 \  m

Generally at equilibrium position the net force acting on the spring is  

            k *  b  -  mg  =  0

=>         k *  0.021   -   2 * 9.8  =  0

=>        k =  933 \  N/m

So

            A  =  0.30  *   \sqrt{\frac{2}{933} }

=>          A  =  0.014 \  m

8 0
3 years ago
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