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2 years ago

Given: G = 6.67259 × 10−11 N m2 /kg2

Physics

1 answer:

8_murik_8 [283]2 years ago

8 0

Answer:

Work done W 2.938*10^9 J

Explanation:

given data:

mass m = 944 Kg

Mass of moon M = 7*10^22 Kg

Radius of the moon R = 1.5*10^6 m

gravitational constant G = 6.67*10^{-11} Nm^2/Kg^2

we know that work done is given as

Work done $W = \frac{GMm}{R}$

$= \frac{6.67*10^{-11}*7*10^{22}*944}{1.5*10^6 m}$

= 2.938*10^9 J

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A soccer field is viewed from above, while a ball is kicked eastward with an initial speed of 10.0 m/s. The ball experiences a c

satela [25.4K]

Answer:

the ball travelled approximately 60 m towards north before stopping

Explanation:

Given the data in the question;

First course : $a_{x}$ = 0.75 m/s², $d_{x}$ = 20 m, $u_{x}$ = 10 m/s

now, form the third equation of motion;

v² = u² + 2as

we substitute

$v_{x}$ ² = (10)² + (2 × 0.75 × 20)

$v_{x}$ ² = 100 + 30

$v_{x}$ ² = 130

$v_{x}$ = √130

$v_{x}$ = 11.4 m/s

for the Second Course:

$u_{y}$ = 11.4 m/s, $a_{y}$ = -1.15 m/s², $v_{y}$ = 0

Also, form the third equation of motion;

v² = u² + 2as

we substitute

0² = (11.4)² + (2 × (-1.15) × $d_{y}$ )

0 = 129.96 - 2.3 $d_{y}$

2.3 $d_{y}$ = 129.96

$d_{y}$ = 129.96 / 2.3

$d_{y}$ = 56.5 m

so;

|d| = √( $d_{x}$ ² + $d_{y}$ ² )

we substitute

|d| = √( (20)² + (56.5)² )

|d| = √( 400 + 3192.25 )

|d| = √( 3592.25 )

|d| = 59.9 m ≈ 60 m

Therefore, the ball travelled approximately 60 m towards north before stopping

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2 years ago

A 6.8 KG object moves with a velocity of 8 M/S what’s it's kinetic energy?

FromTheMoon [43]

Answer:

Explanation:

KE = ½mv² = ½(6.8)8² = 217.6 J

round as appropriate because that result is way too much precision for the inputs provided. Arguably should be 200 J based on the single significant digit of the velocity.

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The dependent variable is the iron in your blood because it depends on the amount of spinach you eat. The independent variable will be the amount of spinach you eat since it doesn’t depend on the iron for anything.

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Answer:

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2 years ago

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