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SashulF [63]
3 years ago
6

Given: G = 6.67259 × 10−11 N m2 /kg2

Physics
1 answer:
8_murik_8 [283]3 years ago
8 0

Answer:

Work done W 2.938*10^9 J

Explanation:

given data:

mass m = 944 Kg

Mass of moon M = 7*10^22 Kg

Radius of the moon R = 1.5*10^6 m

gravitational constant G = 6.67*10^{-11} Nm^2/Kg^2

we know that work done is given as

Work done W = \frac{GMm}{R}

                      = \frac{6.67*10^{-11}*7*10^{22}*944}{1.5*10^6 m}

                      = 2.938*10^9 J

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You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th
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r = radius of the wire = \frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m      (Conversion factor:  1 m = 1000 mm)

\Delta l = change in length  = 1.99 mm = 1.99\times 10^{-3}m

Putting values in above equation, we get:

Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2

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