Calcula qué tan lejos está Saturno del Sol, sabiendo que la luz solar necesita una hora y veinte segundos para llegar a Saturno.

True false according to current atomic theory electrons are in fixed locations

Amanda [17]

That's false. According to current atomic theory and quantum mechanics, an electron is always PROBABLY SOMEWHERE in a fuzzy foggy area around the nucleus of the atom, and that's all we can ever say about it. There's no way to even TELL where the electron is, even if we had the technology to see things that small.

4 0

3 years ago

Resonance structures have _______ connectivity of atoms and _______ distribution of electrons.

Arte-miy333 [17]

Answer:

Resonance structures have same connectivity of atoms and differ only in distribution of electrons.

Explanation:

Atoms supply the electrons from their outer electron shells. Electrons are found free in nature and are grouped around the nucleus into shells. Electrons can be further explained as negatively charged subatomic particle. Electrons have properties of both particles and waves and they can be moved around.

Resonance structures are imaginary structures and not all of them are created equally. Resonance structures have two or more possible electron structures, and, the resonance structures for a particular substance sometimes have different energy and stability. When resonance structures are identical, they are important descriptions of the molecule. The position of the atoms is the same in the various resonance structures of a compound, but the electrons are distributed differently around the structure.

3 0

3 years ago

Transverse waves are sent along a 4.50 m long string with a speed of 85.00 m/s. The string is under a tension of 20.00 N. What i

frutty [35]

Answer:

m = 0.0125 kg

Explanation:

Let us apply the formula for the speed of a wave on a string that is under tension:

$v = \sqrt{\frac{F}{\mu} }$

where F = tension force

μ = mass per unit length

Mass per unit length is given as:

μ = m / l

where m = mass of the string

l = length of the string

This implies that:

$v = \sqrt{\frac{F}{m/l} }\\ \\v = \sqrt{\frac{F * l}{m} }$

Let us make mass, m, the subject of the formula:

$v^2 = \frac{F * l}{m}\\\\m = \frac{F * l}{v^2}$

From the question:

F = 20 N

l = 4.50 m

v = 85 m/s

Therefore:

$m = \frac{20 * 4.5}{85^2}\\\\m = \frac{90}{7225}\\ \\m = 0.0125 kg$

5 0

3 years ago

In a single movable pulley, a load of 500 N is lifted by applying 300 N effort. Calculate MA, VR and efficiency.

galben [10]

Answer:

in pulley there are different kinds.but the most common one are fixed,moveable and compound pulley. in this question we asked about movable pulley.

Explanation:

Given request solutions

L=500N a,M.A=? a,M.A=L/E =5/3

E=300N b,V.R=? b,V.R=2

c,efficiency =? c,£=M.A/V.R=5/6

£=IS NOT THE REAL SYMBOLS OF EFFICIENCY BUT I IS LOOK LIKE THIS

I THINK I HELPED

6 0

2 years ago

An Olympic track runner starts from rest and has an acceleration of 2.4 m/s2 for 3.6 s, then has zero acceleration for the remai

rjkz [21]

Answer:

The runner's speed at the following times would remain 8.64 m/s.

Explanation:

Acceleration definition: Acceleration is rate of change in velocity of an object with respect to time.

In this case, after 3.6 seconds the acceleration is zero, it means that the velocity of the runner after 3.6 seconds is not changing and it will remain constant for the remainder of the race. Now, we have to find the velocity of the runner that he had after 3.6 seconds and that would be the runner's speed for the remainder of the race. For this we use first equation of motion.

First equation of motion: Vf = Vi + a×t

Vf stands for final velocity

Vi stands for initial velocity

a stands for acceleration

t stands for time

In the question, it is mentioned that the runner starts from rest so its initial velocity (Vi) will be 0 m/s.

The acceleration (a) is given as 2.4 m/s²

The time (t) is given as 3.6 s

Now put the values of Vi, a and t in first equation of motion

Vf = Vi + a×t

Vf = 0 + 2.4×3.6

Vf = 2.4×3.6

Vf = 8.64 m/s

So,the runner's speed at the following times would remain 8.64 m/s.

5 0

3 years ago