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1 year ago

7

What must the charge (sign and magnitude) of a 3.45 g particle be for it to remain stationary when placed in a downward-directed

electric field of magnitude 590 N/C

1 answer:

Pani-rosa [81]1 year ago

8 0

charge must be equal to 5.74 ×10⁻⁵

In the question it is said that the particle remains stationary which means the the net force on the particle is zero. So, the counterbalancing forces must be equal which means weight is equal to upward electric force.

→ Fnet =0

→ mg = qE

substituting the values we get :

0.00345 × 9.81 = q × 590

→ q = 5.74 ×10⁻⁵

Hence the charge must be equal to 5.74 ×10⁻⁵.

Learn more about charges here:

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