Starter
Explanation:
Turn the ignition switch to start and release the key immediately or you could destroy the starter.
The car starter is used to cause ignition in the internal combustion engine in order to fire the piston and cause mechanical motion. The starter is used to start the cyclic process of the internal combustion engine.
- Once the engine starts by igniting the starter, it is best to release it.
- The starter ensures that the spark plug is engaged and the motor is brought into work.
- If the ignition is still engaged, the process continues repeatedly and it can damage the starter of the car.
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Answer:
because the gravitational pull is maximum at the poles and decreases as it comes down toward the equator.
Let us situate this on the x axis, and let our uniform line of charge be positioned on the interval <span>(−L,0]</span> for some large number L. The voltage V as a function of x on the interval <span>(0,∞)</span> is given by integrating the contributions from each bit of charge. Let the charge density be λ. Thus, for an infinitesimal length element <span>d<span>x′</span></span>, we have <span>λ=<span><span>dq</span><span>d<span>x′</span></span></span></span>.<span>V(x)=<span>1/<span>4π<span>ϵ0</span></span></span><span>∫line</span><span><span>dq/</span>r</span>=<span>λ/<span>4π<span>ϵ0</span></span></span><span>∫<span>−L</span>0</span><span><span>d<span>x/</span></span><span>x−<span>x′</span></span></span>=<span>λ/<span>4π<span>ϵ0</span></span></span><span>(ln|x+L|−ln|x|)</span></span>
Answer:
R = 0.21 Ω
Explanation:
the formula:
R = r x l/A
R = (44 x 10-⁸ Ωm) x 1.5 / (π x (1 x 10-³ m)²)
R = 6.6 x 10-⁷ / 3.14 x 10-⁶
R = 0.21 Ω
15 N = 15 kg m / s² =
= 15 · 1/14.59 slug · 1 / 0.3048 =
= 15 · 0.06854 · 3.24254 =
= 3.33 lb
Answer: 15 N is equal to 3.33 pounds.
