Answer:
M.Mass = 120 g/mol
Explanation:
Data Given:
Volume = V = 0.0650 L
Temperature = T = 547 °C = 820.15 K
Pressure = P = 70.5 kPa = 0.695 atm
Gas Constant = R = 0.082057 L.atm.mol⁻¹.K⁻¹
Formula Used:
Assuming that the gas is ideally then according to ideal gas equation,
P V = n R T
Solving for n,
n = P V / R T
Putting Values,
n = (0.695 atm × 0.0650 L) ÷ (0.082057 L.atm.mol⁻¹.K⁻¹ × 820.15 K)
n = 6.71 × 10⁻⁴ moles
Now, Knowing that,
Moles = Mass / M.Mass
Or,
M.Mass = Mass / Moles
Putting values,
M.Mass = 8.06 × 10⁻² g / 6.71 × 10⁻⁴ mol
M.Mass = 120 g/mol
Answer:
24.2 mL.
Explanation:
<em>Assuming constant temperature</em>, we can solve this problem using <em>Boyle's law</em>, which states:
Where:
We <u>input the data</u>:
- 0.98 bar * 25 mL = 1.013 bar * V₂
And <u>solve for V₂</u>:
The closest option is the second one: 24.2 mL.
.........................................
When the antimatter is atomic antihydrogen, a small amount of it is mixed with excess atomic hydrogen (gathered from interstellar space during flight).
<h3>What is antimatter ?</h3>
According to contemporary physics, antimatter is described as being made up of the opposite particles from "ordinary" matter, or their "partners." Only a few nanograms of antiparticles have been created artificially, but tiny quantities of antiparticles are produced every day at particle accelerators and in natural processes like cosmic ray collisions and some types of radioactive decay. However, only a small portion of these antiparticles have been successfully bound together in experiments to form antiatoms. Antimatter has never been built in a macroscopic amount due to its extremely high cost, complexity in synthesis, and handling.
A particle and its antiparticle, such as a proton and an antiproton, theoretically have the same mass but the opposite electric charge and other variations in quantum numbers.
To learn more about antimatter from the given link:
brainly.com/question/518346
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Answer:
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