Answer:- 475 mL.
Solution:- It's based on Boyle's gas law. At constant temperature, "The volume of the gas is inversely proportional to the pressure."
Equation for this law is written as:
P and V stands for pressure and volume where as the subscripts 1 and 2 are for initial and final values.
Initial pressure is 6.20 atm and it asks to calculate the initial volume. Final pressure is 9.150 atm and the final volume is 322 mL.
Let's plug in the values in the equation and solve it for initial volume:
On dividing both sides by 6.20 atm:
= 475 mL
So, the originally the gas container volume was 475 mL.
Answer:
Explanation:
The formula for the heat absorbed is
q = mCΔT
Trial 1
m = 30.0 g
ΔT = 40.0 – 0 = 40.0 °C
q₁ = 30.0 × 4.184 × 40.0 = 5020 J
Trial 2
m = 40.0 g
ΔT = 40.0 – 30.0 = 10.0 °C
q₂ = 40.0 × 4.184 × 10.0 = 1670 J
q₁ - q₂ = 5020 – 1670 = 3350 J
1) State the balanced chemical reaction
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
2) State the molar ratios:
1 mol H2SO4 : 2 mol NaOH
3) Set the proportions using the number of moles of one rectant and x for the unknown one>
1 mol H2SO4 / 2 mol NaOH = x mol H2SO4 / 0.75 mol NaOH
=> x = 0.75 mol NaOH * [1 mol H2SO4 / 2 mol NaOH]
x = 0.375 mol H2SO4
4) Calculate the mass using the molar mass of H2SO4, MM.
MM = 2*1g/mol + 32.1 g/mol + 4*16 g/mol = 98.1 g/mol
mass = # of moles * molar mass = 0.375 mol * 98.1 g/mol = 36.79 g.
Answer: 36.8 grams