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Volgvan
3 years ago
10

When a plant undergoes respiration it?

Chemistry
1 answer:
VikaD [51]3 years ago
8 0
<span>Respiration breaks down the sugar inside its cells.  i have answered the question WHEN A PLANT UNDERGOES RESPIRATIONS IT WHAT HAPPENS</span>
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Convert 100 miles to inches (there are 5280 ft in one mile)
expeople1 [14]

Answer:

Explanation:

100 miles * [ 5280 feet / 1 mile] * 12 inches / 1 foot]

100 * 5280 * 12 inches

6336000 inches in 100 miles

8 0
3 years ago
Will someone actually help me and not just something random
Novosadov [1.4K]

Answer:

D

Explanation:

8 0
4 years ago
31) To extend a length of 1.00 inches, 2.54 x 10^8 average sized atoms would have to be placed in a straight line (in other word
Phoenix [80]

Answer:

Here's the conversion factor you need:

1 Kilometer   =   39370 inches

So, for your question we want to go 405,696 km....

405696 km   x   39370 inches/ 1 km  =   15972283464 inches

                       

15972283464 inches   x   2.54 x10^8 atoms/1 inch   =   4.05 x 10^18 atoms

                                     

4 0
3 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0
3 years ago
Given that a 19.00 g milk chocolate bar contains 11.50 g of sugar, calculate the percentage of sugar present in 19.00
Jet001 [13]

Explanation:

check the steps in the attached image

6 0
2 years ago
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