The concentration of the diluted solution will be 2.44%.
<h3>Dilution problem</h3>
From the equation of dilution:
(M1)(V1) = (M2)(V2).
where M1 = concentration before dilution, M2 = concentration after dilution, V1 = volume before dilution, and V2 = volume after dilution.
In this case:
V1 = 17.06 mL
V2 = 50.00 mL
M1 = 7.16%
M2 = ?
M2 = (M1)(V1)/(V2)
= 7.16 x 17.06/50
= 2.44%
Thus, the concentration of the diluted solution is 2.44%.
More on dilution can be found here: brainly.com/question/21323871
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Ba(OH)₂ is a strong base, therefore completely ionises in the solution as follows
Ba(OH)₂ --> Ba²⁺ + 2OH⁻
1 mol of Ba(OH)₂ gives out 2 mol of OH⁻
therefore number of OH⁻ moles are twice the amount of Ba(OH)₂ moles in the solution
hence,
[OH⁻] = 2[Ba(OH)₂]
therefore hydroxide ion concentration = 2 x 1.37 x 10⁻⁵ M
[OH⁻] = 2.74 x 10⁻⁵ M
coefficient = 2.74
exponent = -5
4 clumping beauty and Gove the other
The number of dots represents the amount of valence electrons, which is the same as the last digit of the elements group number in ptof.
