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Arturiano [62]
3 years ago
5

What kind of bond is created by week electrical attraction between polar molecules

Chemistry
1 answer:
Aleksandr [31]3 years ago
3 0

Answer:

Hydrogen bond

Explanation:

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How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?
Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

pH= -log[H]\\pH= -log (\frac{kw}{[OH]})

8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}

[OH]=1.69E-6

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

Cu(OH)_2 -> Cu^{2+} + 2OH^-

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

Kps= [Cu^{2+}] [OH]^2

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

Kps= s*(2s+1.69E-6)^2

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is s=4.96E-8 mol/L

Now, let us calculate the moles in 1 L:

moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles

7 0
3 years ago
5. You are investigating an arson scene and you find a corpse in the rubble, but you suspect that the victim did not die as a re
Marina CMI [18]

Answer:

See the answer below.

Explanation:

Fire has three major components:

  • Heat
  • Smoke
  • Gases ( in form of CO, CO2 etc)

If the victim had died as a result of the fire, he/he would have inhaled smoke and hot gases from the fire. These components would have resulted in traces of burns and soot deposition in the trachea and lungs as well as traces of CO in the blood of the victim.

If the analysis of the victim's corpse does not reflect some of the results above, it can be effectively concluded that the victim has been dead before the fire.

<em>The single most important indicator of death by the fire would be the presence of CO in the blood of the victim's corpse. All others might be to a less significant degrees.</em>

8 0
3 years ago
Ethanol (C2H5OH) is produced from the fermentation of sucrose in the presence of enzymes.
madam [21]

actual yield of ethanol = 305.0g

molar mass of sucrose = 342g

molar mass of ethanol  =46g

mass of sucrose = 665g

mole of sucrose = mass / molar mass = 665/342

mole of sucrose =1.9 mole

sucrose :  C2H5OH

       1      :  4

     1.9     : 1.9x4 =7.6 mole of C2H5OH are formed

mass (therotical yield ) of C2H5OH= mole x mass

mass (therotical yield ) of C2H5OH= 7.6 x 46 = 349.6g

percent yields of ethanol =  actual /therotical x100

=305/349.6x100 = 87.24 %

6 0
3 years ago
The_____ Force between two objects which depends _____ and Their______ apart
zlopas [31]
The Gravitational Force between two objects which depends on masses and their separation apart
5 0
3 years ago
Read 2 more answers
A balloon is launched when the temperature is 15 oC and the pressure is 0.918 atm. Its volume is 11.1 L. It rises in the air unt
ivann1987 [24]

Answer:

The new volume is 7,606.96 Liter.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas in the balloon = 0.918 atm

P_2 = final pressure of gas in the balloon = 0.0012 atm

V_1 = initial volume of gas in the balloon = 11.1 L

V_2 = final volume of gas in the balloon = ?

T_1 = initial temperature of gas in the balloon = 15^oC=273+15=288K

T_2 = final temperature of gas in the balloon = -15^oC=273-15=258K

Now put all the given values in the above equation, we get:

\frac{0.918 atm\times 11.1 L}{288 K}=\frac{0.0012 atm\times V_2}{258 K}

V_2=\frac{0.918 atm\times 11.1 L\times 258 K}{288 K\times 0.0012 atm}

V_2=7,606.97 L

The new volume is 7,606.96 Liter.

5 0
3 years ago
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