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3 years ago

Describe how the properties of the compound carbon monoxide (CO) differ from the properties of the elements in the compound.

Physics

2 answers:

abruzzese [7]3 years ago

8 0

Answer:

A compound is a pure substance made of two or more elements chemically combined in a set ratio. ... If a different ratio of carbon atoms and oxygen atoms are seen in a formula, you have a different compound. For example, carbon monoxide—a gas produced in car engines—has the formula CO.

Harlamova29_29 [7]3 years ago

7 0

Answer:

Carbon monoxide is a highly poisonous, odorless, colorless, and tasteless gas. It is very flammable in air over a wide range of concentrations and burns in air with a bright blue flame . It becomes a liquid at 81.62 K.

the elements in the compound carbon and oxygen.

oxygen is also colorless, odorless and tasteless gas but it's not poisonous.

as we use it for breathing purpose whereas too much oxygen can be toxic.

carbon is solid and very brittle. diamond and graphite are two most common forms of carbon.

When elements are chemically combined, they form compounds having properties that are different from those of the uncombined elements

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It is found that the most probable speed of molecules in a gas at equilibrium temperature

kaheart [24]

Answer:

$\frac{T_2}{T_1} = 1$

Explanation:

The root mean square velocity of the gas at an equilibrium temperature is given by the following formula:

$v = \sqrt{\frac{3RT}{M} }$

where,

v = root mean square velocity of molecules:

R = Universal Gas Constant

T = Equilibrium Temperature

M = Molecular Mass of the Gas

Therefore,

For T = T₁ :

$v = \sqrt{\frac{3RT_1}{M} }$

For T = T₂ :

$v = \sqrt{\frac{3RT_2}{M} }$

Since both speeds are given to be equal. Therefore, comparing both equations, we get:

$\sqrt{\frac{3RT_1}{M} }=\sqrt{\frac{3RT_2}{M} }\\\\\frac{T_2}{T_1} = 1$

8 0

2 years ago

Two soccer players kick a soccer ball back and forth along a straight line. The first player kicks the ball 16 m to the right to

Oliga [24]

Answer:

The total distance is $d_t =19.1 m$

The displacement is

$D_t = 12.9m$

Explanation:

From the question we are told that

Distance traveled by the ball for first player $d_f = 16m$ to the right

Distance traveled by the ball for second player $d_s = 3.1 m$ to the left

The total distance traveled by the ball is mathematically represented as

$d_t = d_f + d_s$

Substituting values

$d_t = 16 + 3.1$

$d_t =19.1 m$

The displacement is mathematically represented as

$D_t = d_f -d_s$

This is because displacement deal with direction and from the question we are told that right is positive and left is negative

Substituting values

$D_t = 16 -3.1$

$D_t = 12.9m$

5 0

3 years ago

A 55.0-kg lead ball is dropped from the Leaning Tower of Pisa. The tower is 55.0 m high. What is the speed of the ball after it

PolarNik [594]

Answer:

The speed of the ball is 9.07 m/s.

Explanation:

Given that,

Mass of the lead ball, m = 55 kg

Height of the tower, h = 55 m

We need to find the speed of the ball it has traveled 4.20 m downward, x = 4.2 meters

The initial speed of the ball will be 0 as it was at rest initially. Let v is the speed of the ball after it has traveled 4.20 m downward. It is a case of equation of motion such that :

$v^2-u^2=2ax$