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alexandr402 [8]
3 years ago
8

Why is it important to consider experimental error in all the empirical results presented?

Physics
1 answer:
NemiM [27]3 years ago
3 0
Because when your running any experiment there will always be an experimental error so always be ready for it so that you can correct that error in your experiment
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goblinko [34]

Answer:

Explanation:

initial velocity u = 32.7 m /s

final velocity v = 50.3 m /s

displacement s = 44500 m

acceleration a = ?

v² = u² + 2 a s

50.3² = 32.7² + 2 x a x 44500

2530.09 = 1069.29 + 89000a

a .016 m /s²

time taken t = ?

v = u + at

50.3 = 32.7 + .016 t

t = 1100 s

6 0
2 years ago
What happens when someone is walking across the carpeted room then touches a metal door knob
igomit [66]
Static electricity travels to the door knob because of the friction caused by the feet on the carpet. the friction traveled through the person, to their hand, and to the door knob because it is the best conductor.
6 0
3 years ago
B c<br>_ - _<br>a b<br>( a=3 b=-5 c=6)​
Pachacha [2.7K]
(-5)/3 - 6/(-5)
You can solve it now :)
7 0
2 years ago
Solve for x. 4(x+1)≤4x+3
alexdok [17]
4x + 4 < 4x + 3 (expand it)
4 < 3 (cancel 4x on both sides)
Since 4 < 3 is not true there is no solution.

Answer: NO SOLUTION.
3 0
3 years ago
Read 2 more answers
How is the electrostatic force affected when the magnitude of a charge is doubled?
BaLLatris [955]
The magnitude of the electrostatic force between two charges is given by:
F=k_e  \frac{q_1 q_2}{r^2}
where
ke is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges

We can see that the magnitude of the force is directly proportional to the charges. This means that when one of the charges is doubled, the magnitude of the electrostatic force will double as well, so the correct answer is
A) <span>The magnitude of the electrostatic force doubles</span>
4 0
3 years ago
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