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alexandr402 [8]
3 years ago
8

Why is it important to consider experimental error in all the empirical results presented?

Physics
1 answer:
NemiM [27]3 years ago
3 0
Because when your running any experiment there will always be an experimental error so always be ready for it so that you can correct that error in your experiment
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What is the density of an object with a volume of 20 cm3 and a mass of 40g?
melisa1 [442]
Density = mass/volume
Density = 40g/20cm^3
Density = 2g/cm^3
3 0
3 years ago
Which statements about electric field lines are correct? Check all that apply.
slava [35]

Answer:

they cross over one another between charge.

7 0
4 years ago
Materials will have different energies associated with the electrons inside them. This is related to how strongly bound they are
andrey2020 [161]

Answer:

E = 401.3 eV

Explanation:

As we know that the thinnest gap in the direction of metal is given as

t = 3.09 nm

so here we can say that lowest energy of photon will not able to break this electron from above thickness

so we will have

E = \frac{hc}{\lambda}

here we have

hc = 1240 nm-eV}

also we have

\lambda = 3.09 nm

so we will have

E = \frac{1240}{3.09} eV

E = 401.3 eV

7 0
4 years ago
PLZZZ HELP
matrenka [14]

B. A sandbar is formed by water. A sand dune is formed by wind.

4 0
3 years ago
A projectile is shot from the edge of a cliff above the ground level with initial velocity of at an angle with the horizontal. (
Xelga [282]

Answer:

t = √2y/g

Explanation:

This is a projectile launch exercise

a) The vertical velocity in the initial instants (v_{oy} = 0) zero, so let's use the equation

     y =v_{oy} t -1/2 g t²

     y= - ½ g t²

     t = √2y/g

b) Let's use this time and the horizontal displacement equation, because the constant horizontal velocity

     x = vox t

     x = v₀ₓ √2y/g

c) Speeds before touching the ground

     vₓ = vox = constant

     v_{y} = v_{oy} - gt

     v_{y} = 0 - g √2y/g

    v_{y}  = - √2gy

    tan θ = Vy / vx

    θ = tan⁻¹ (vy / vx)

    θ = tan⁻¹ (√2gy / vox)

d) The projectile is higher than the cliff because it is a horizontal launch

6 0
4 years ago
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