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2 years ago

9

Give short definitions for the following terms: 1. All Atomic number 2. Mass number 3. Atomic weight 4. Isotope 5. Natural abund

ance 6. Atomic mass unit

1 answer:

son4ous [18]2 years ago

8 0

Explanation:

Hello ! Let's solve this!

1-atomic number: the atomic number is the number of protons that the atom has

2-mass number: is the amount of protons plus the amount of neutrons in the atom

3-atomic weight: average of the masses of an atom per 1/12 of the mass of carbon

4-isotope: it is the same element that has the same number of protons but a different number of neutrons

5-natural abundance: measures the amount of isotopes of an element in nature

6-unit of atomic mass: (uma) is a unit that is equivalent to 1/12 of the carbon atom

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What's an interesting fact about Aristotle?

gladu [14]

Answer:

Image result for What's an interesting fact about Aristotle?

Interesting Aristotle Facts: 1-5

Aristotle was born somewhere around 384 BCE. ...

His father was Nicomachus. ...

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After the death of Nicomachus, Proxenus – husband of Aristotle's sister Arimneste, became the guardian of young Aristotle.

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2 years ago

Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Alenkasestr [34]

Answer: 1.289 m

Explanation:

The path the cobra's venom follows since it is spitted until it hits the ground, is described by a parabola. Hence, the equations for parabolic motion (which has two components) can be applied to solve this problem:

<u>x-component: </u>

$x=V_{o}cos\theta t$ (1)

Where:

$x$ is the horizontal distance traveled by the venom

$V_{o}=3.10 m/s$ is the venom's initial speed

$\theta=47\°$ is the angle

$t$ is the time since the venom is spitted until it hits the ground

<u>y-component: </u>

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.44 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Let's begin with (2) to find the time it takes the complete path:

$0=0.44 m+3.10 m/s sin\theta(47\°)+\frac{-9.8m/s^{2} t^{2}}{2}$ (3)

Rewritting (3):

$-4.9 m/s^{2} t^{2} + 2.267 m/s t + 0.44 m=0$ (4)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (5)

Where:

$a=-4.9 m/s^{2$

$b=2.267 m/s$

$c=0.44 m$

Substituting the known values:

$t=\frac{-2.267 \pm \sqrt{2.267^{2}-4(-4.9)(0.44)}}{2(-4.9)}$ (6)

Solving (6) we find the positive result is:

$t=0.609 s$ (7)

Substituting (7) in (1):

$x=(3.10 m/s)cos(47\°)(0.609 s)$ (8)

We finally find the horizontal distance traveled by the venom:

$x=1.289 m$

7 0

3 years ago

Which statements are true about the periodic table apex

TiliK225 [7]

Can be numbered in 2 different ways, one box represents one element, and organized by atomic number

7 0

3 years ago

How far did the object travel by the end of eight seconds, according to the graph above?

Ulleksa [173]

Answer:

<em>The object traveled 4 cm by the end of eight seconds.</em> Correct: A)

Explanation:

<u>Speed vs Time Graph</u>

In a speed-time graph, speed is plotted on the vertical axis and time is plotted on the horizontal axis. If the graph is a horizontal line, the speed is constant, if the line is sloped up, the speed is increasing and the acceleration is positive and constant, and if the line is sloped down, the speed is decreasing and the acceleration is negative and constant.

The distance traveled by the object can be found by calculating the area under the graph and above the x-axis.

The graph provided shows two different zones: the first 4 seconds, the speed is constant at 1 cm/s, and the last 4 seconds, the speed is zero, i.e. the object is not moving.

The area behind the first zone is a rectangle of height 1 cm/s and base 4 sec, thus the distance is 1 * 4 = 4 centimeters.

The second zone corresponds to an object at rest, thus no distance is traveled.

The object traveled 4 cm by the end of eight seconds.

A) Correct. As shown above

B) The distance traveled is 4 cm. Incorrect

C) The distance traveled is 4 cm. Incorrect

D) The distance traveled is 4 cm. Incorrect

6 0

3 years ago

The magnitude of the momentum of an object is 64 kilogram meters per second. If the magnitude of te velocity is doubled, the mag

dsp73

Answer:

$128 \frac{kg*m}{s}$

Explanation:

$P=m*v\\if double velocity:\\P=m*2v=2m*v\\$

7 0

3 years ago