Please solve for me am confused

Which of the following best describes the way that scientists make observations

horrorfan [7]

I don’t see any answer choice but the best way is asking questions about the natural phenomenon, making hypothesis, and predicting the consequences in the hypothesis.

6 0

3 years ago

An ethernet cable is 3.80 m long and has a mass of 0.210 kg. A transverse pulse is produced by plucking one end of the taut cabl

Tasya [4]

Answer:

$T=94.54N$

Explanation:

The tension in a cable is given by:

$T=\mu v^2(1)$

Where $\mu$ is the mass density of the cable and v is the speed of the cable's pulse. These values are defined as:

$\mu=\frac{m}{L}(2)\\v=\frac{d}{t}$

The pulse makes four trips down and back along the cable, so $d=4(2L)$

$v=\frac{8L}{t}(3)$

Replacing (2) and (3) in (1), we calculate the tension in the cable:

$T=\frac{m}{L}(\frac{8L}{t})^2\\T=\frac{64mL}{t^2}\\T=\frac{64(0.21kg(3.80m))}{(0.735s)^2}\\T=94.54N$

3 0

3 years ago

A measurement such as 74% humidity is an example of what?

BartSMP [9]

Example of Relative humidity. B.

6 0

3 years ago

Read 2 more answers

Explain these three questions and give answers please I don't get this at all I need help on these!!!

Greeley [361]

3. All are hydrocarbons and all are in the eth- group i.e. all have two carbon atoms. Ethane is an alkane, ethene is an alkene and ethyne is an alkyne.
4. No C=C double bonds, only single C-C bonds. Saturated with hydrogen atoms (as many C-H bonds as possible).
5. As branching increases, boiling points decrease. (Molecules exert intermolecular forces of attraction between each other and these are stronger when they are closer together. Branching makes it harder for the hydrocarbon molecules to pack closely together therefore these forces are weaker and it takes lesser energy to break them.)

8 0

3 years ago

Two electrons are separated by a distance of

dlinn [17]

Answer:

(1) $2.56\times10^{-17} N$ away from each other.

Explanation:

Two charged particles interact due an electrostatic force each of them feels due the other one, and the magnitude of that electric force is:

$F_{e}=k\frac{\mid q_{1}q_{2}\mid}{r^{2}}$

With q1, q2 the charges of the particles, k the Coulomb's constant and r the distance between the particles. The force is the same on each of the particles due Newton's third law. Then the force is:

$F_{e}=(9.0\times10^{9})\frac{\mid e *e\mid}{(3.00\times10^{-6})^{2}}=(9.0\times10^{9})\frac{\mid (1.6\times10^{-19})^2\mid}{(3.00\times10^{-6})^{2}}$

$F_{e}=2.56\times10^{-17} N$

The direction of the force is given by the sign of the charges, if the charges have the same sign the force between them is repulsive, and if the charges are opposite the force between the are attractive. Because we have two electrons and both have the same negative charge, the force between them is repulsive so the force is pointing away from each other.

6 0

3 years ago

Please solve for me am confused​

Please solve for me am confused