Based on the enthalpy of the reaction, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).
<h3>What is heat of reaction?</h3>
The heat of reaction or enthalpy change is the heat absorbed or evolved when reactant molecules react to form products.
According the enthalpy value of the reaction, 4 moles of ammonia require 1530 kJ of heat for its formation.
Molar mass of ammonia = 17 g
Mass of 4 moles of ammonia = 4 × 17 = 68 g
1850 g of ammonia will require = 1850 × 1530/68 = 41625 kJ of heat.
Therefore, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).
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Answer:
A.
Carbon dioxide
Explanation:
In a tissue that metabolizes glucose via the pentose phosphate pathway, C-1 of glucose would be expected to end up principally in Carbon dioxide
Answer:
Number 3,Concentration of hydrogen ions in solution.
Brainliest would be appreciated :))
The compound HClO4, when placed in water, will dissociate into the ions, H+ and ClO4-. Therefore, the 2.0 M solution will also form 2.0 M H+. The pH is calculated through the equation,
pH = -log[H+]
Substituting,
pH = -log[2] = -0.3
Thus, the pH of the solution is -0.3.
Following reaction arise between Br2 and Cl2
Br2 + Cl2 → 2BrCl
(1mole) (1mole) (2moles)
From above balanced reaction, it can be seen that 1 mole of Br2 reacts with 1 mole of Cl2 to form 2 mole of BrCl
Thus, when <span>2.74 mol Cl2 reacts with excess Br2, 2.74 X 2 = 5.48 moles of BrCl will be formed. </span>
