Answer:
a) 5.03 kg m/s
b) 10.03 kg m/s
Explanation:
Hi!
Let us consider the origin of coordinates at the pitcher, and pointing directly towards the initial direction of the ball. Therefore, the angle of the velocity with respect to the x axis is -35° (below the horizontal).
The components of the initial momentum are:
px = (0.3 kg)(15 m/s) cos(-35° ) = 4.5 cos(-35° ) kg m/s = 3.69 kg m/s
py = 4.5 sin(-35° ) kg m/s = -2.581 kg m/s
The final momentum will be:
a)
pfx = 0
pfy = - (20 m/s) (0.3 kg) = -6 m/s
And the difference in momentum is:
dpy = pfy - py = -3.419 kg m/s
dpx = pfx - px = -3.69 kg m/s
And its magnitude:
dp = √(dpy^2 + dpx^2) = 5.03 kg m/s
b)
pfx = -6 kg m/s
pfy = 0
And the difference in momentum is:
dpx = pfx - px = -9.69 kg m/s
dpy = pfy - py = 2.581 kg m/s
And its magnitude:
dp = √(dpy^2 + dpx^2) = 10.03 kg m/s
