What is the condition for the machine to be perfect?
2 answers:
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Answer:
V₂=4.57 x 10³ L
Explanation:
Given that
V₁= 2.88 x 10³ L
P₁=722 mm Hg
T₁ = 19°C
T₁ =292 K
P₂=339 mm Hg
T₂= - 55°C
T₂=218 K
Lets take final volume = V₂
We know that ideal gas equation
PV = m R T
By applying mass conservation
V₂=4.57 x 10³ L
Therefore volume will be 4.57 x 10³ L
The volume of a cube is given by:
where L is the measure of each side (which corresponds to its width, since all sides of a cube are equal).
Plugging the data of the problem, L=32.1 cm, inside the equation, we find the volume: