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Fudgin [204]
3 years ago
12

A plane flies from base camp to lake a, 200 km away in the direction 20.0° north of east. after dropping off supplies it flies t

o lake b, which is 230 km at 30.0° west of north from lake
a. graphically determine the distance and direction from lake b to the base camp.
Physics
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Distance of lake a is 200 km at 20 degree north of east

distance between lake a and b is 230 km at 30 degree west of north

now the distance between base and lake b is given as

d = d_1 + d_2

given that

d_1 = 200 cos20 i + 200 sin20 j

d_1 = 187.94 i + 68.4 j

d_2 = -230 sin30 i + 230 cos30 j

d_2 = -115 i + 199.2 j

now the total distance is

d = (187.94 - 115)i + (199.2 + 68.4)j

d = 72.94 i + 267.6 j

now the magnitude of the distance is given as

d = \sqrt{72.94^2 + 267.6^2}

d = 277.4

also the direction is given as

\theta = tan^{-1}\frac{267.6}{72.94}

\theta = 74.7 degree

<em>so it is 277.4 km at 74.7 degree North of East</em>

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Answer:

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As we know that

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As we know that star radiates wavelength and this wavelength is inverse proportional to the temperature of the star.

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Which would be the most reliable source for information about the toxicity of an industrial chemical?
kvasek [131]
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At an air show, a stunt pilot performs a vertical loop-the-loop in a circle of radius 3.63 x 103 m. During this performance the
san4es73 [151]

Answer:

189 m/s

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5 0
3 years ago
The acceleration of gravity is -9.8 m/s2. A sling shot fires a rock straight up into the air with a speed of +39.2 m/s. 1. what
Vanyuwa [196]

Given that,

The acceleration of gravity is -9.8 m/s²

Initial velocity, u = 39.2 m/s

Time, t = 2 s

To find,

The final velocity of the shot.

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Let v is the final velocity of sling shot. Using first equation of motion to find it.

v = u +at

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4 0
2 years ago
A rod of length L and mass M has a nonuniform mass distribution. The linear mass density (mass per length) is λ=cx2, where x is
grigory [225]

Answer:

Explanation:

λ=c x²

c = λ / x²

λ is mass / length

so its dimensional formula is ML⁻¹

x is length so its dimensional formula is L

c = λ / x²

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B )

We shall find out the mass of the rod with the help of given expression of mass per unit length and equate it with given mass that is M

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we consider a small strip of rod of length dx at x distance away from middle point

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C ) Moment of inertia of rod

∫dmx²

= ∫λdxx²

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= ∫cx⁴dx

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= (c / 80) L⁵

= (12 M L⁻³/80)L⁵

= 3/20 ML²

=

=

4 0
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