What happens when you brake earphones in to smaller and smaller pieces

Suppose this comet were to hit the earth at 40000 km/h and fuse with it. by how much would it change our planet's velocity? (the

sattari [20]

change in velocity = final velocity - initial velocity = v - u

for comet:
uc = initial velocity of comet (before impact)
vc = final velocity of comet
mc= mass of comet

uc = 40000 kmph
vc = ?
mc= 10 x 10^14 kg

for probe:

up = initial velocity of probe (before impact)
vp = final velocity of probe
mp= mass of probe

up= 37000 kmph
vp= ?
mp= 372 kg

Now,
by principle of conservation of momentum

(mc x uc) - (mp x up) = (mc x vc) + (mp x vp)

Since probe is in comet after collision, vp= vc = V

then,

(mc x uc) - (mp x up) = V (mc + mp )
V = [(mc x uc) - (mp x up)] / (mc + mp )

= ((10 × 10^14 × 40000) - (372 × 37000)) ÷ ((10 × 10^14) + 372)

= ???

then,

change in velocity of the comet = ??? - (40000) =

8 0

3 years ago

An ice skater of mass m = 60 kg coasts at a speed of v = 0.8 m/s past a pole. At the distance of closest approach, her center of

IrinaVladis [17]

Answer:

1.78 rad/s

1.70344 rad/s

Explanation:

v = Velocity = 0.8 m/s

m = Mass of person = 60 kg

$r_1$ = Distance between center of mass of person and pole = 0.45 m

$r_2$ = New distance between center of mass of person and pole = 0.46 m

I = Moment of inertia

Angular speed is given by

$\omega_1=\dfrac{v}{r_1}\\\Rightarrow \omega_1=\dfrac{0.8}{0.45}\\\Rightarrow \omega_1=1.78\ rad/s$

The angular speed is 1.78 rad/s

In this system the angular momentum is conserved

$L_1=L_2\\\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow mr_1^2\omega_1=mr_2^2\omega_2\\\Rightarrow \omega_2=\dfrac{r_1^2\omega_1}{r_2^2}\\\Rightarrow \omega_2=\dfrac{0.45^2\times 1.78}{0.46^2}\\\Rightarrow \omega_2=1.70344\ rad/s$

The new angular speed is 1.70344 rad/s

7 0

2 years ago

A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 6.55x10-2 kg/s. The density of the gasoline is 740

klasskru [66]

Answer:

speed = 3.95 m/s

Explanation:

area = π x radius^2

area = π x (2.67 x 10^-3)^2

volume flow rate = area x speed

volume / time = area x speed

density = mass / volume

volume = mass / density

mass / (density x time) = area *speed

mass flow rate = mass / time

mass flow rate / density = area x speed

6.55 x 10^-2 / 740 = pi * (2.67 x 10^-3)^2 * speed

speed =8.8514 x 10-5 /2.2396 x 10-5 m/s

speed = 3.95 m/s

6 0

3 years ago

An average force of 328 N acts for a time interval of 0.05s on a golf ball

blagie [28]

Depends on how strong you are. People can hit it anywhere between a few inches and 500 yards.

4 0

2 years ago

Which process requires more energy: completely vaporizing 1 kg of saturated liquid water at 1 atm pressure or completely vaporiz

Lilit [14]

The correct answer would be the first option. The process that would need more energy would be vaporizing 1 kg of saturated liquid water at a pressure of 1 atmosphere. This can be seen from the latent heat of vaporization of each system. For the saturated water at 1 atm, the latent heat is equal to 40.7 kJ per mole while, at 8 atm, the latent heat is equal to 36.4 kJ per mole. The latent heat of vaporization is the amount of heat needed in order to vaporize a specific amount of substance without any change in the temperature. As we can observe, more energy is needed by the liquid water at 1 atm.

7 0

2 years ago