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Andru [333]
3 years ago
8

A student pulls a sled of mass m = 82.0 kg with a force of F = 160N, and the force makes an angle of θ = 15 degrees with respect

to the horizontal. Ignoring friction the normal force exerted on the sled by the ground is A) 649.05N;
B) 762.2N;
C) 527.90N;
D) 845.01N;
Physics
2 answers:
Minchanka [31]3 years ago
8 0

Answer:B

Explanation:

Given

mass of sledge=82 kg

Force on sledge=160 N

degree=15^{\circ}

force has two component sin and cos

Normal reaction =mg-F\sin \theta

N=82\times 9.8-160\sin 15

N=803.6-41.41=762.19 N

prisoha [69]3 years ago
8 0

Answer:

The normal force exerted on the sled by the ground is 762.2 N.

(B) is correct option.

Explanation:

Given that,

Mass of sled m=82.0 kg

Force = 160 N

Angle = 15 degrees

We need to calculate the component of force

X- component,

F_{x}=F\cos\theta

Put the value into the formula

F_{x}=160\cos15

F_{x}=154.54\ N

Y- component,

F_{y}=F\sin\theta

Put the value into the formula

F_{y}=160\sin15

F_{y}=41.41\ N

We need to calculate the force due to gravity

Using formula of force

F_{g} = mg

F_{g}=82.0\times9.8

F_{g}=803.6\ N

We need to calculate the normal force

Using formula of normal force

F_{n}=F_{g}-F_{y}

Put the value into the formula

F_{n}=803.6-41.41

F_{n}=762.2\ N

Hence, The normal force exerted on the sled by the ground is 762.2 N.

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