Question

A student pulls a sled of mass m = 82.0 kg with a force of F = 160N, and the force makes an angle of θ = 15 degrees with respect to the horizontal. Ignoring friction the normal force exerted on the sled by the ground is A) 649.05N;
B) 762.2N;
C) 527.90N;
D) 845.01N;

Answer 1

Answer:B

Explanation:

Given

mass of sledge=82 kg

Force on sledge=160 N

degree$=15^{\circ}$

force has two component sin and cos

Normal reaction $=mg-F\sin \theta$

$N=82\times 9.8-160\sin 15$

$N=803.6-41.41=762.19 N$

Answer 2

Answer:

The normal force exerted on the sled by the ground is 762.2 N.

(B) is correct option.

Explanation:

Given that,

Mass of sled m=82.0 kg

Force = 160 N

Angle = 15 degrees

We need to calculate the component of force

X- component,

$F_{x}=F\cos\theta$

Put the value into the formula

$F_{x}=160\cos15$

$F_{x}=154.54\ N$

Y- component,

$F_{y}=F\sin\theta$

Put the value into the formula

$F_{y}=160\sin15$

$F_{y}=41.41\ N$

We need to calculate the force due to gravity

Using formula of force

$F_{g} = mg$

$F_{g}=82.0\times9.8$

$F_{g}=803.6\ N$

We need to calculate the normal force

Using formula of normal force

$F_{n}=F_{g}-F_{y}$

Put the value into the formula

$F_{n}=803.6-41.41$

$F_{n}=762.2\ N$

Hence, The normal force exerted on the sled by the ground is 762.2 N.